89 lines
3.6 KiB
TeX
89 lines
3.6 KiB
TeX
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\documentclass[a4paper,12pt]{/media/documents/Cours/Prof/Enseignements/tools/style/classExo}
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\usepackage{/media/documents/Cours/Prof/Enseignements/2015_2016}
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% Title Page
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\titre{Introduction à la trigonométrie}
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\classe{Troisième}
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\date{mars 2014}
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\pagestyle{empty}
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\geometry{left=5mm,right=5mm, bottom= 10mm, top=10mm}
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\begin{document}
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Compléter le tableau suivant en fonction des triangles.
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\begin{tabular}{|c|*{6}{c|}}
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\hline
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Triangle & Hypoténuse & coté adjacent & coté opposé & angle & $\frac{\mbox{coté adjacent}}{\mbox{Hypoténuse}}$ & $\frac{\mbox{coté opposé}}{\mbox{Hypoténuse}}$ \\
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\hline
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ABC & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
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\hline
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DEF & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
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\hline
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GHI & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
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\hline
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JKL & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
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\hline
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MNP & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
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\hline
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\end{tabular}
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\begin{center}
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\includegraphics[scale=0.4]{./fig/triangles}
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\end{center}
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\begin{Exo}
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\textbf{Avec la figure suivante, calculer la longueur $BA$.}
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\\[0.3cm]
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\begin{minipage}[h]{0.2\textwidth}
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\includegraphics[scale=0.15]{./fig/triangleABC}
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\end{minipage}
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\begin{minipage}[h]{0.8\textwidth}
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\textit{Questions à se poser}
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\begin{itemize}
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\item On connait
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\begin{center}
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hypoténuse\hspace{0.5cm} opposé \hspace{0.5cm}adjacent \hspace{0.5cm}angle
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\end{center}
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\item On cherche
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\begin{center}
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hypoténuse\hspace{0.5cm} opposé \hspace{0.5cm}adjacent \hspace{0.5cm}angle
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\end{center}
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\end{itemize}
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\begin{itemize}
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\item On utilise la formule
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\begin{eqnarray*}
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\cos( \widehat{BAC}) = \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.5cm}
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\sin( \widehat{BAC}) = \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.5cm}
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\tan( \widehat{BAC}) = \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}}
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\end{eqnarray*}
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\end{itemize}
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\end{minipage}
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\textit{Rédaction:}
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\noindent\fbox{\parbox{\linewidth-2\fboxrule-2\fboxsep}{
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.\\
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\parbox{1cm}{\dotfill} est un triangle rectangle en \parbox{0.5cm}{\dotfill} donc
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\begin{eqnarray*}
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\parbox{1cm}{\dotfill}(\widehat{BAC}) &=& \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.7cm} \textit{(avec les lettres)}\\[0.3cm]
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\parbox{1cm}{\dotfill}(\parbox{1cm}{\dotfill}) &=& \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.7cm} \textit{(avec les chiffres)} \\[0.3cm]
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\parbox{1cm}{\dotfill} &=& \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.7cm} \textit{(avec les chiffres)} \\[0.3cm]
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BA & = & \parbox{1cm}{\dotfill} \times \parbox{1cm}{\dotfill} = \parbox{1cm}{\dotfill}
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\end{eqnarray*}
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Donc $BA = \parbox{1cm}{\dotfill}$
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}}
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\end{Exo}
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "master"
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%%% End:
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