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% Title Page
\titre{Introduction à la trigonométrie}
\classe{Troisième}
\date{mars 2014}

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\geometry{left=5mm,right=5mm, bottom= 10mm, top=10mm}

\begin{document}


Compléter le tableau suivant en fonction des triangles.

\begin{tabular}{|c|*{6}{c|}}
    \hline
    Triangle & Hypoténuse & coté adjacent & coté opposé & angle & $\frac{\mbox{coté adjacent}}{\mbox{Hypoténuse}}$ & $\frac{\mbox{coté opposé}}{\mbox{Hypoténuse}}$ \\
    \hline
    ABC & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
    \hline
    DEF & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
    \hline
    GHI & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
    \hline
    JKL & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
    \hline
    MNP & ...... = ...... & ...... = ...... & ...... = ...... & ...... = ...... & $\frac{......}{......} = ......$ & $\frac{......}{......} = ......$ \\
    \hline
\end{tabular}

\begin{center}
    \includegraphics[scale=0.4]{./fig/triangles}
\end{center}

\begin{Exo}

        \textbf{Avec la figure suivante, calculer la longueur $BA$.}
    \\[0.3cm]

    \begin{minipage}[h]{0.2\textwidth}
        \includegraphics[scale=0.15]{./fig/triangleABC}
    \end{minipage}
    \begin{minipage}[h]{0.8\textwidth}
        \textit{Questions à se poser}
        \begin{itemize}
            \item On connait
                \begin{center}
                hypoténuse\hspace{0.5cm} opposé \hspace{0.5cm}adjacent \hspace{0.5cm}angle
                \end{center}
            \item On cherche
                \begin{center}
                hypoténuse\hspace{0.5cm} opposé \hspace{0.5cm}adjacent \hspace{0.5cm}angle
                \end{center}
        \end{itemize}
        \begin{itemize}
            \item On utilise la formule
                \begin{eqnarray*}
                    \cos( \widehat{BAC}) = \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.5cm}
                    \sin( \widehat{BAC}) = \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.5cm}
                    \tan( \widehat{BAC}) = \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}}
                \end{eqnarray*}
                
        \end{itemize}
    \end{minipage}
        \textit{Rédaction:}

        \noindent\fbox{\parbox{\linewidth-2\fboxrule-2\fboxsep}{
        .\\
        \parbox{1cm}{\dotfill} est un triangle rectangle en \parbox{0.5cm}{\dotfill} donc
        \begin{eqnarray*}
            \parbox{1cm}{\dotfill}(\widehat{BAC}) &=& \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.7cm} \textit{(avec les lettres)}\\[0.3cm]
            \parbox{1cm}{\dotfill}(\parbox{1cm}{\dotfill}) &=& \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.7cm} \textit{(avec les chiffres)} \\[0.3cm]
            \parbox{1cm}{\dotfill} &=& \frac{\parbox{2cm}{\dotfill}}{\parbox{2cm}{\dotfill}} \hspace{0.7cm} \textit{(avec les chiffres)} \\[0.3cm]
            BA & = & \parbox{1cm}{\dotfill} \times \parbox{1cm}{\dotfill} = \parbox{1cm}{\dotfill}
        \end{eqnarray*}
        Donc $BA = \parbox{1cm}{\dotfill}$
}}
\end{Exo}

\end{document}

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