\documentclass[a4paper,12pt]{article} \usepackage{myXsim} \author{Benjamin Bertrand} \title{Géométrie repérée - Cours} \date{2022-01-13} \pagestyle{empty} \begin{document} \maketitle \bigskip \section*{Milieu d'un segment} \begin{propriete}[Coordonnée du milieu d'un segment] \begin{minipage}{0.5\linewidth} Soit $M$ et $N$ deux points quelconques et $K$ le milieu du segment $[MN]$. Alors \begin{itemize} \item L'abscisse de $K$ est la moyenne des abscisses de $M$ et $N$ \[ x_K = \frac{x_M + x_N}{2} \] \item L'ordonnée de $K$ est la moyenne des ordonnées de $M$ et $N$ \[ y_K = \frac{y_M + y_N}{2} \] \end{itemize} \end{minipage} \hfill \begin{minipage}{0.4\linewidth} \begin{tikzpicture}[scale=1.2] \draw[->, very thick] (-1, 0) -- (4, 0); \draw[->, very thick] (0, -1) -- (0, 4); \draw (0, 0) node [below left] {0}; \draw (1, 0) node {+} node [below left] {1}; \draw (0, 1) node {+} node [below left] {1}; \draw (1.3, 1.4) node {+} node [below left] {$M$}; \draw (1.3, 0) node {+} node [below] {$x_M$}; \draw (0, 1.4) node {+} node [left] {$y_M$}; \draw[dashed] (1.3, 1.4) --(1.3, 0); \draw[dashed] (1.3, 1.4) --(0, 1.4); \draw (3.3, 3.4) node {+} node [below right] {$N$}; \draw (3.3, 0) node {+} node [below] {$x_N$}; \draw (0, 3.4) node {+} node [left] {$y_N$}; \draw[dashed] (3.3, 3.4) --(3.3, 0); \draw[dashed] (3.3, 3.4) --(0, 3.4); \draw (2.3, 2.4) node {+} node [below right] {$K$}; \draw (2.3, 0) node {+} node [below] {$x_K$}; \draw (0, 2.4) node {+} node [left] {$y_K$}; \draw[dashed] (2.3, 2.4) --(2.3, 0); \draw[dashed] (2.3, 2.4) --(0, 2.4); \draw (1.3, 1.4) -- node [midway, sloped] {//} (2.3, 2.4) -- node [midway, sloped] {//} (3.3, 3.4); \draw (1.3, 0) -- node [midway, sloped] {$\bullet$} (2.3, 0) -- node [midway, sloped] {$\bullet$} (3.3, 0); \draw (0, 1.4) -- node [midway, sloped] {$\diamond$} (0, 2.4) -- node [midway, sloped] {$\diamond$} (0, 3.4); \end{tikzpicture} \end{minipage} \end{propriete} \paragraph{Exemple}: Coordonnée de $I$ milieu du segment $[AB]$ avec $A(23; 45)$ et $B (-3; 12)$ \[ x_I = \frac{x_A + x_B}{2} = \frac{23 + (-3)}{2} = 10 \qquad \qquad y_I = \frac{y_A + y_B}{2} = \frac{45 + 12}{2} = 28.5 \] Les coordonnées de $I$ sont $(10; 28.5)$. \end{document}