307 lines
6.9 KiB
Plaintext
307 lines
6.9 KiB
Plaintext
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{
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"cells": [
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{
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"cell_type": "markdown",
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"id": "c66ea101",
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"metadata": {},
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"source": [
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"# Programmation et suites\n",
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"\n",
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"La programmation est un outil efficace pour calculer les termes d'une suite. C'est ce que nous allons apprendre à utiliser."
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]
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},
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{
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"cell_type": "markdown",
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"id": "e7a96b1f",
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"metadata": {},
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"source": [
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"## Calcul termes à termes\n",
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"\n",
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"On reprend notre exemple de l'étude de l'épidémie de Covid\n",
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"\n",
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"Sauf mention explicite, les questions suivantes devront être répondu en utilisant Python.\n",
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"\n",
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"### Premier modèle - arthimétique\n",
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"\n",
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"On suppose que le nombre de malades est modélisé par une suite arithmétique de raison +28 et de premier terme 130 (ce qui correspond à la date du 1/03/2020).\n",
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"\n",
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"1.Calculer le nombre de malade le 2/03/2020"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "e54fa4a8",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "9936312e",
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"metadata": {},
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"source": [
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"2. Calculer le nombre de malade le 3/03/2020"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "e7059cf4",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "2a26f718",
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"metadata": {},
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"source": [
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"3. Calculer le nombre de malade le 10/03/2020"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "bf3d5969",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "57369bfc",
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"metadata": {},
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"source": [
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"### Deuxième modèle - géométrique\n",
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"\n",
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"On suppose que le nombre de malades est modélisé par une suite géométrique de raison x1.64 et de premier terme 130 (correspondant à la date du 01/03/2020)\n",
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"\n",
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"1. Calculer le nombre de malade le 2/03/2020"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "b4f3efd7",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "96e8cd82",
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"metadata": {},
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"source": [
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"2. Calculer le nombre de malade le 3/03/2020"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "05f6f285",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "2b46ca12",
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"metadata": {},
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"source": [
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"3. Calculer le nombre de malade le 10/03/2020"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "1d9709a9",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "f9b84648",
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"metadata": {},
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"source": [
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"## Répétitions finies - Boucle for\n",
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"\n",
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"Le travail initié dans la partie précédente est répétitive surtout si l'on souhaite calculer le nombre de malades à la fin du mois (le 31/03/2020) ou plus tard.\n",
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"\n",
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"Quand on fait plusieur fois la même chose, on peut utiliser un boucle `for` en python. Voici un exemple de son utilisation:"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"id": "b96aca04",
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"metadata": {},
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"outputs": [],
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"source": [
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"u = 3\n",
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"for i in range(10):\n",
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" u = u + 5 "
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]
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},
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{
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"cell_type": "markdown",
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"id": "f2106ede",
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"metadata": {},
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"source": [
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"1. Que fait le programme précédent? Combien vaut `u` à la fin du programme? Quelle type de suite peut modéliser le contenu de la variable `u` (vous préciserez les paramètres)?"
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]
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},
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{
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"cell_type": "raw",
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"id": "41396015",
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"metadata": {},
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "03289e29",
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"metadata": {},
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"source": [
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"2. Afficher la variable `somme` pour vérfier vos suppositions."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "416f8bb9",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "5f7dfe3c",
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"metadata": {},
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"source": [
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"3. Adapter le programme précédent pour calculer le nombre de malade au 16/03/2020 avec le modèle arithmétique."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "c829159a",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "55791f40",
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"metadata": {},
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"source": [
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"4. Quelle sera le nombre de malade avec le 31/03/2020 avec le modèle géométrique?"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "ed17e2da",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "e337d3ce",
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"metadata": {},
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"source": [
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"## Répétition bornées - Boucle While\n",
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"\n",
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"Il est possible d'utiliser un autre type de boucles, les boucles `while`. `while` signifie **tant que** en anglais.\n",
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"\n",
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"À la différence des boucles `for` où l'on rentre un nombre de répétitions, les boucles `while` s'arrète à une condition donnée.\n",
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"\n",
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"Voici un exemple."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 4,
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"id": "0144ea7c",
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"metadata": {},
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"outputs": [],
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"source": [
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"jour = 0\n",
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"u = 3\n",
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"while u < 30:\n",
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" u = u*2\n",
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" jour = jour + 1\n",
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" "
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]
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},
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{
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"cell_type": "markdown",
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"id": "53eff1a1",
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"metadata": {},
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"source": [
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"1. Que fait le programme précédent? Combien vaut `u` à la fin? Combien vaut `jour`? Quelle type de suite peut modéliser le contenu de la variable `u` (vous préciserez les paramètres)?"
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]
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},
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{
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"cell_type": "raw",
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"id": "e752f3cd",
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"metadata": {},
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "3283fa60",
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"metadata": {},
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"source": [
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"2. Adapter le programme précédent pour calculer le nombre de jours avant que le nombre de malades dépasse 1000 avec la suite arithmétique."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "fef6fcb3",
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"metadata": {},
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"outputs": [],
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"source": []
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},
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{
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"cell_type": "markdown",
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"id": "b5ff5bbb",
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"metadata": {},
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"source": [
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"3. Adapter le programme pour calculer le nombre de jours avant que le nombre de malades dépasse 100 000 avec la suite géométrique."
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "156707ce",
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"metadata": {},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3 (ipykernel)",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.10.9"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 5
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}
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