Feat: ajoute les exercices techniques pour les calculs de fractions
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2nd/01_Proportion_et_fractions/1_exercises_tech.tex
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64
2nd/01_Proportion_et_fractions/1_exercises_tech.tex
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\begin{exercise}[subtitle={Multiplication de fractions}, step={3}, origin={Création}, topics={ Proportion et fractions }, tags={ Statistiques, Fractions }, mode={\searchMode}]
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Faire les calculs suivants
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\begin{multicols}{4}
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\begin{enumerate}[label={\Alph*=}]
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\item $\dfrac{- 6}{3} + \dfrac{- 7}{3}$
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\item $\dfrac{- 10}{5} + \dfrac{6}{5}$
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\item $\dfrac{7}{10} + \dfrac{3}{90}$
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\item $\dfrac{10}{81} + \dfrac{5}{9}$
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\item $\dfrac{7}{9} + \dfrac{3}{10}$
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\item $\dfrac{8}{5} + \dfrac{3}{7}$
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\item $\dfrac{1}{a} + \dfrac{1}{2a}$
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\item $\dfrac{3}{5a} + \dfrac{1}{4a}$
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\end{enumerate}
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\end{multicols}
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\end{exercise}
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\begin{solution}
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\begin{enumerate}[label={\Alph*=}]
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\item $\dfrac{- 6}{3} + \dfrac{- 7}{3}=\dfrac{- 6 - 7}{3}=\dfrac{- 13}{3} = \dfrac{- 13}{3}$
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\item $\dfrac{- 10}{5} + \dfrac{6}{5}=\dfrac{- 10 + 6}{5}=\dfrac{- 4}{5} = \dfrac{- 4}{5}$
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\item $\dfrac{7}{10} + \dfrac{3}{90}=\dfrac{7 \times 9}{10 \times 9} + \dfrac{3}{90}=\dfrac{63}{90} + \dfrac{3}{90}=\dfrac{63 + 3}{90}=\dfrac{66}{90} = \dfrac{11}{15}$
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\item $\dfrac{10}{81} + \dfrac{5}{9}=\dfrac{10}{81} + \dfrac{5 \times 9}{9 \times 9}=\dfrac{10}{81} + \dfrac{45}{81}=\dfrac{10 + 45}{81}=\dfrac{55}{81} = \dfrac{55}{81}$
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\item $\dfrac{7}{9} + \dfrac{3}{10}=\dfrac{7 \times 10}{9 \times 10} + \dfrac{3 \times 9}{10 \times 9}=\dfrac{70}{90} + \dfrac{27}{90}=\dfrac{70 + 27}{90}=\dfrac{97}{90} = \dfrac{97}{90}$
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\item $\dfrac{- 6}{3} + \dfrac{- 7}{3}=\dfrac{- 6 - 7}{3}=\dfrac{- 13}{3} = \dfrac{- 13}{3}$
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\item $\dfrac{1}{a} + \dfrac{1}{2a} = \dfrac{2}{2a} + \dfrac{1}{2a} = \dfrac{2+1}{2a} = \dfrac{3}{2a}$
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\item $\dfrac{3}{5a} + \dfrac{1}{4a} = \dfrac{12}{20a} + \dfrac{5}{20a} = \dfrac{12+5}{2a} = \dfrac{17}{2a}$
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\end{enumerate}
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\end{solution}
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\begin{exercise}[subtitle={Multiplication de fractions}, step={3}, origin={Création}, topics={ Proportion et fractions }, tags={ Statistiques, Fractions }, mode={\searchMode}]
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Faire les calculs suivants
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\begin{multicols}{4}
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\begin{enumerate}[label={\Alph*=}]
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\item $\dfrac{7}{8} \times \dfrac{- 10}{8}$
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\item $B = \dfrac{3}{10} \times \dfrac{7}{10}$
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\item $\dfrac{3}{4} \times \dfrac{9}{12}$
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\item $\dfrac{2}{30} \times \dfrac{4}{10}$
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\item $\dfrac{9}{3} \times \dfrac{9}{7}$
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\item $\dfrac{5}{4} \times \dfrac{3}{7}$
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\item $\dfrac{1}{a} * \dfrac{1}{2a}$
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\item $\dfrac{3}{5a} * \dfrac{1}{4a}$
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\end{enumerate}
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\end{multicols}
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\end{exercise}
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\begin{solution}
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\begin{enumerate}[label={\Alph*=}]
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\item $\dfrac{7}{8} \times \dfrac{- 10}{8}=\dfrac{7(- 10)}{8 \times 8}=\dfrac{- 70}{64} = \dfrac{- 35}{32}$
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\item $\dfrac{3}{10} \times \dfrac{7}{10}=\dfrac{3 \times 7}{10 \times 10}=\dfrac{21}{100} = \dfrac{21}{100}$
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\item $\dfrac{3}{4} \times \dfrac{9}{12}=\dfrac{3 \times 9}{4 \times 12}=\dfrac{27}{48} = \dfrac{9}{16}$
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\item $\dfrac{2}{30} \times \dfrac{4}{10}=\dfrac{2 \times 4}{30 \times 10}=\dfrac{8}{300} = \dfrac{2}{75}$
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\item $\dfrac{9}{3} \times \dfrac{9}{7}=\dfrac{9 \times 9}{3 \times 7}=\dfrac{81}{21} = \dfrac{27}{7}$
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\item $\dfrac{7}{8} \times \dfrac{- 10}{8}=\dfrac{7(- 10)}{8 \times 8}=\dfrac{- 70}{64} = \dfrac{- 35}{32}$
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\item $\dfrac{1}{a} \times \dfrac{1}{2a} = \dfrac{1\times 1}{a\times 2a} = \dfrac{1}{2a^2}$
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\item $\dfrac{3}{5a} \times \dfrac{1}{4a} = \dfrac{3\times 1}{5a\times 4a} = \dfrac{3}{20a^2}$
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\end{enumerate}
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\end{solution}
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@ -22,5 +22,6 @@
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\maketitle
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\input{exercises.tex}
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\input{1_exercises_tech.tex}
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\end{document}
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2nd/01_Proportion_et_fractions/bopytex_config.py
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2nd/01_Proportion_et_fractions/bopytex_config.py
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# bopytex_config.py
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from mapytex.calculus.random import expression as random_expression
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from mapytex import render
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import random
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random.seed(0) # Controlling the seed allows to make subject reproductible
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render.set_render("tex")
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direct_access = {
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"random_expression": random_expression,
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}
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@ -43,16 +43,17 @@
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\end{exercise}
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\begin{solution}
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\def\arraystretch{2}
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\begin{enumerate}
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\item $\frac{120}{150} = \frac{4}{5} = 0.8 = 80\%$
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\item $\frac{5}{22} \approx 0.22 = 22\%$
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\item $\dfrac{120}{150} = \dfrac{4}{5} = 0.8 = 80\%$
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\item $\dfrac{5}{22} \approx 0.22 = 22\%$
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\item
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\begin{tabular}{|p{4cm}|*{4}{c|}}
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\hline
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Camping & Les flots bleu & Cascade magique & Le tronc dégarni & La vallée plate\\
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\hline
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Proportion en fraction & $\frac{0}{35}$ & $\frac{10}{15}$ & $\frac{40}{75}$ & $\frac{100}{200}$ \\
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Proportion en fraction & $\dfrac{0}{35}$ & $\dfrac{10}{15}$ & $\dfrac{40}{75}$ & $\dfrac{100}{200}$ \\
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\hline
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Proportion en décimal & 0 & 0.66 & 0.53 & 0.5 \\
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\hline
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@ -60,6 +61,7 @@
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\hline
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\end{tabular}
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\end{enumerate}
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\def\arraystretch{1.5}
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\end{solution}
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@ -106,29 +108,31 @@
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\end{exercise}
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\begin{solution}
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\def\arraystretch{2}
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\begin{tabular}{|*{4}{c|}}
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\hline
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Proportion & Fraction irréductible & Effectifs associés & Valeur décimale \\
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\hline
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10\% & $\frac{1}{10}$ & 10 pour 100, c'est comme 1 pour 10 & 0.1\\
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10\% & $\dfrac{1}{10}$ & 10 pour 100, c'est comme 1 pour 10 & 0.1\\
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\hline
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20\% & $\frac{1}{5}$ & 20 pour 100, c'est comme 1 pour 5 & 0.2\\
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20\% & $\dfrac{1}{5}$ & 20 pour 100, c'est comme 1 pour 5 & 0.2\\
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\hline
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25\% & $\frac{1}{4}$ & 25 pour 100, c'est comme 1 pour 4 & 0.25\\
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25\% & $\dfrac{1}{4}$ & 25 pour 100, c'est comme 1 pour 4 & 0.25\\
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\hline
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33.3\% & $\frac{333}{1000}$ & 33.3 pour 100, c'est comme 333 pour 1000 & 0.333\\
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33.3\% & $\dfrac{333}{1000}$ & 33.3 pour 100, c'est comme 333 pour 1000 & 0.333\\
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\hline
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50\% & $\frac{1}{2}$ & 50 pour 100, c'est comme 1 pour 2 & 0.5 \\
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50\% & $\dfrac{1}{2}$ & 50 pour 100, c'est comme 1 pour 2 & 0.5 \\
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\hline
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60\% & $\frac{3}{5}$ & 60 pour 100, c'est comme 3 pour 5 & 0.6 \\
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60\% & $\dfrac{3}{5}$ & 60 pour 100, c'est comme 3 pour 5 & 0.6 \\
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\hline
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66.7\% & $\frac{667}{1000}$ & 66.7 pour 100, c'est comme 667 pour 1000 & 0.667\\
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66.7\% & $\dfrac{667}{1000}$ & 66.7 pour 100, c'est comme 667 pour 1000 & 0.667\\
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\hline
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75\% & $\frac{3}{4}$ & 75 pour 100, c'est comme 3 pour 4 & 0.75 \\
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75\% & $\dfrac{3}{4}$ & 75 pour 100, c'est comme 3 pour 4 & 0.75 \\
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\hline
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100\% & 1 & 100 pour 100, c'est comme 1 pour 1 & 1\\
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\hline
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\end{tabular}
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\def\arraystretch{1.5}
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\end{solution}
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\begin{exercise}[subtitle={Techniques}, step={1}, origin={MEpC}, topics={ Proportion et fractions }, tags={ Statistiques, Fractions }, mode={\trainMode}]
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@ -148,19 +152,21 @@
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\end{exercise}
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\begin{solution}
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\begin{multicols}{3}
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\begin{enumerate}
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\item $\frac{20}{100} \times 190 = 38$
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\item $\frac{2}{3} \times 126 = 84$
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\item $\frac{42}{100} = \frac{31}{50} = 0.42$
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\item $\frac{78}{100} = \frac{39}{50} = 0.78$
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\item $\frac{1,5}{5} = \frac{3}{10} = 0.3$
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\item $\frac{1500}{2300} = \frac{15}{23} \approx 0.65$
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\item $\frac{30}{100} \times 400 = 120$
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\item $\frac{0.6}{100} \times \np{2 000 000} = \np{12 000}$
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\item $ \frac{14}{0.4} = 35$
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\item $ \frac{150 000}{0.75} = 200 000$
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\item $ \frac{5\times 30}{0.24} = 625$
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\item $\dfrac{20}{100} \times 190 = 38$
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\item $\dfrac{2}{3} \times 126 = 84$
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\item $\dfrac{42}{100} = \dfrac{31}{50} = 0.42$
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\item $\dfrac{78}{100} = \dfrac{39}{50} = 0.78$
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\item $\dfrac{1,5}{5} = \dfrac{3}{10} = 0.3$
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\item $\dfrac{1500}{2300} = \dfrac{15}{23} \approx 0.65$
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\item $\dfrac{30}{100} \times 400 = 120$
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\item $\dfrac{0.6}{100} \times \np{2 000 000} = \np{12 000}$
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\item $ \dfrac{14}{0.4} = 35$
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\item $ \dfrac{150 000}{0.75} = 200 000$
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\item $ \dfrac{5\times 30}{0.24} = 625$
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\end{enumerate}
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\end{multicols}
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\end{solution}
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\begin{exercise}[subtitle={Radars}, step={1}, origin={MEpC}, topics={ Proportion et fractions }, tags={ Statistiques, Fractions }, mode={\groupMode}]
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\begin{enumerate}
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\item Est-il possible de trouver deux nombres entiers distincts $a$ et $b$ tels que:
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\[
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\frac{1}{a} + \frac{1}{b} = 1
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\dfrac{1}{a} + \dfrac{1}{b} = 1
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\]
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\item Est-il possible de trouver deux nombres entiers distincts $a$, $b$ et $c$ tels que:
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\[
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\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = 1
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\dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c} = 1
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\]
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\item Avec 4 nombres? 5? Et plus?
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\end{enumerate}
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@ -213,11 +219,11 @@
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\end{multicols}
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\item Indiquez sur les disques les fractions correspondantes
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\[
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\frac{1}{2} \qquad
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\frac{1}{3} \qquad
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\frac{1}{4} \qquad
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\frac{1}{8} \qquad
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\frac{1}{12} \qquad
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\dfrac{1}{2} \qquad
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\dfrac{1}{3} \qquad
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\dfrac{1}{4} \qquad
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\dfrac{1}{8} \qquad
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\dfrac{1}{12} \qquad
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\]
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\item Reconstituez un disque complet à l'aide de 3 portions.
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\item Reconstituez un disque complet à l'aide de 4 portions.
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\maketitle
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\input{exercises.tex}
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%\printcollection{banque}
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%\printsolutions{exercises}
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\input{1_exercises_tech.tex}
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\end{document}
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2nd/01_Proportion_et_fractions/tpl_exercises_tech.tex
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2nd/01_Proportion_et_fractions/tpl_exercises_tech.tex
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\begin{exercise}[subtitle={Multiplication de fractions}, step={3}, origin={Création}, topics={ Proportion et fractions }, tags={ Statistiques, Fractions }, mode={\searchMode}]
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Faire les calculs suivants
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\begin{multicols}{4}
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\begin{enumerate}[label={\Alph*=}]
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%- set A = random_expression("{a} / {b} + {c} / {b}", ["a!=b", "c!=b", "b > 1"], global_config={"rejected":[-1, 0, 1]})
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\item $\Var{A}$
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%- set B = random_expression("{a} / {b} + {c} / {b}", ["a!=b", "c!=b", "b > 1"], global_config={"rejected":[-1, 0, 1]})
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\item $\Var{B}$
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%- set C = random_expression("{a} / {b} + {c} / {d*b}", ["a!=b", "c!=b", "b > 1"], global_config={"min_max":(1, 10)})
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\item $\Var{C}$
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%- set D = random_expression("{a} / {d*b} + {c} / {b}", ["a!=b", "c!=b", "b > 1"], global_config={"min_max":(1, 10)})
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\item $\Var{D}$
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%- set E = random_expression("{a} / {b} + {c} / {d}", ["a!=b", "c!=b", "gcd(b, d) == 1"], global_config={"min_max":(1, 10)})
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\item $\Var{E}$
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%- set F = random_expression("{a} / {b} + {c} / {d}", ["a!=b", "c!=b", "gcd(b, d) == 1"], global_config={"min_max":(1, 10)})
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\item $\Var{F}$
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\item $\dfrac{1}{a} + \dfrac{1}{2a}$
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\item $\dfrac{3}{5a} + \dfrac{1}{4a}$
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\end{enumerate}
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\end{multicols}
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\end{exercise}
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\begin{solution}
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\begin{enumerate}[label={\Alph*=}]
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\item $\Var{A.simplify().explain() | join('=')} = \Var{A.simplify().simplified}$
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\item $\Var{B.simplify().explain() | join('=')} = \Var{B.simplify().simplified}$
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\item $\Var{C.simplify().explain() | join('=')} = \Var{C.simplify().simplified}$
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\item $\Var{D.simplify().explain() | join('=')} = \Var{D.simplify().simplified}$
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\item $\Var{E.simplify().explain() | join('=')} = \Var{E.simplify().simplified}$
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\item $\Var{A.simplify().explain() | join('=')} = \Var{A.simplify().simplified}$
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\item $\dfrac{1}{a} + \dfrac{1}{2a} = \dfrac{2}{2a} + \dfrac{1}{2a} = \dfrac{2+1}{2a} = \dfrac{3}{2a}$
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\item $\dfrac{3}{5a} + \dfrac{1}{4a} = \dfrac{12}{20a} + \dfrac{5}{20a} = \dfrac{12+5}{2a} = \dfrac{17}{2a}$
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\end{enumerate}
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\end{solution}
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\begin{exercise}[subtitle={Multiplication de fractions}, step={3}, origin={Création}, topics={ Proportion et fractions }, tags={ Statistiques, Fractions }, mode={\searchMode}]
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Faire les calculs suivants
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\begin{multicols}{4}
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\begin{enumerate}[label={\Alph*=}]
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%- set A = random_expression("{a} / {b} * {c} / {b}", ["a!=b", "c!=b", "b > 1"], global_config={"rejected":[-1, 0, 1]})
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\item $\Var{A}$
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%- set B = random_expression("{a} / {b} * {c} / {b}", ["a!=b", "c!=b", "b > 1"], global_config={"rejected":[-1, 0, 1]})
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\item $B = \Var{B}$
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%- set C = random_expression("{a} / {b} * {c} / {d*b}", ["a!=b", "c!=b", "b > 1"], global_config={"min_max":(1, 10)})
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\item $\Var{C}$
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%- set D = random_expression("{a} / {d*b} * {c} / {b}", ["a!=b", "c!=b", "b > 1"], global_config={"min_max":(1, 10)})
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\item $\Var{D}$
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%- set E = random_expression("{a} / {b} * {c} / {d}", ["a!=b", "c!=b", "gcd(b, d) == 1"], global_config={"min_max":(1, 10)})
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\item $\Var{E}$
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%- set F = random_expression("{a} / {b} * {c} / {d}", ["a!=b", "c!=b", "gcd(b, d) == 1"], global_config={"min_max":(1, 10)})
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\item $\Var{F}$
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\item $\dfrac{1}{a} * \dfrac{1}{2a}$
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\item $\dfrac{3}{5a} * \dfrac{1}{4a}$
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\end{enumerate}
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\end{multicols}
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\end{exercise}
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\begin{solution}
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\begin{enumerate}[label={\Alph*=}]
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\item $\Var{A.simplify().explain() | join('=')} = \Var{A.simplify().simplified}$
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\item $\Var{B.simplify().explain() | join('=')} = \Var{B.simplify().simplified}$
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\item $\Var{C.simplify().explain() | join('=')} = \Var{C.simplify().simplified}$
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\item $\Var{D.simplify().explain() | join('=')} = \Var{D.simplify().simplified}$
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\item $\Var{E.simplify().explain() | join('=')} = \Var{E.simplify().simplified}$
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\item $\Var{A.simplify().explain() | join('=')} = \Var{A.simplify().simplified}$
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\item $\dfrac{1}{a} \times \dfrac{1}{2a} = \dfrac{1\times 1}{a\times 2a} = \dfrac{1}{2a^2}$
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\item $\dfrac{3}{5a} \times \dfrac{1}{4a} = \dfrac{3\times 1}{5a\times 4a} = \dfrac{3}{20a^2}$
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\end{enumerate}
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\end{solution}
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