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use sympy to compute root of polynomDeg2

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Lafrite 2015-04-07 09:51:12 +02:00
parent 7f79e23cd3
commit 3af50d0eab
1 changed files with 12 additions and 7 deletions
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19
pymath/polynomDeg2.py
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@ -3,10 +3,12 @@
from .polynom import Polynom
from .expression import Expression
from .fraction import Fraction
from .operator import op
from .random_expression import RdExpression
from math import sqrt
from sympy import sqrt, latex
#from sympy.fractions import Fraction as sp.Fraction
__all__ = ["Polynom_deg2"]
@ -125,7 +127,8 @@ class Polynom_deg2(Polynom):
def roots(self, after_coma = 2):
""" Compute roots of the polynom
/!\ Can't manage exact solution because of pymath does not handle sqare root yet
/!\ Can't manage nice rendering because of sqrt.
It use sympy to compute roots
# TODO: Pymath has to know how to compute with sqare root |mar. févr. 24 18:40:04 CET 2015
@ -134,16 +137,18 @@ class Polynom_deg2(Polynom):
[]
>>> P = Polynom_deg2([1, 2, 1])
>>> P.roots()
[-1.0]
[-1]
>>> P = Polynom_deg2([-1, 0, 1])
>>> P.roots()
[-1.0, 1.0]
['-1', '1']
>>> P = Polynom_deg2([1, 4, 1])
>>> P.roots()
['-2 - \\\\sqrt{3}', '-2 + \\\\sqrt{3}']
"""
# TODO: Use sympy to compute those |mar. avril 7 07:31:42 CEST 2015
if self.delta > 0:
self._roots = [round((-self.b - sqrt(self.delta))/(2*self.a),after_coma), round((-self.b + sqrt(self.delta))/(2*self.a),after_coma)]
self._roots = [latex((-self.b - sqrt(self.delta))/(2*self.a)), latex((-self.b + sqrt(self.delta))/(2*self.a))]
elif self.delta == 0:
self._roots = [round(-self.b /(2*self.a), after_coma)]
self._roots = [Fraction(-self.b,2*self.a).simplify()]
else:
self._roots = []
return self._roots