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remove repetition in equation solving

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This commit is contained in:
Benjamin Bertrand 2016-03-26 05:38:21 +03:00
parent 0b3d162a8e
commit 58f447b3b2
2 changed files with 17 additions and 14 deletions
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23
pymath/calculus/equation.py
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@ -13,6 +13,12 @@ from .random_expression import RdExpression
__all__ = ['Equation'] __all__ = ['Equation']
def equals(new, old):
print("new -> ", new)
print("old -> ", old)
return new, old
class Equation(object): class Equation(object):
"""A calculus expression. Today it can andle only expression with numbers later it will be able to manipulate unknown""" """A calculus expression. Today it can andle only expression with numbers later it will be able to manipulate unknown"""
@ -100,8 +106,7 @@ class Equation(object):
r = self.r_exp, r = self.r_exp,
) )
#@no_repetition(lambda x, y: (x[0] == y[0]) & (x[1] == y[1])) @no_repetition(lambda x, y: (x[0] == y[0]) & (x[1] == y[1]), ['',''])
@no_repetition()
def solve(self): def solve(self):
r"""Solve the equation but yielding each steps r"""Solve the equation but yielding each steps
@ -110,7 +115,6 @@ class Equation(object):
... print(" = ".join([str(j) for j in i])) ... print(" = ".join([str(j) for j in i]))
x + 123 = 0 x + 123 = 0
x + 123 - 123 = 0 - 123 x + 123 - 123 = 0 - 123
x + 123 - 123 = 0 - 123
x + 123 - 123 = -123 x + 123 - 123 = -123
x = -123 x = -123
>>> e = Equation("2x = x + 2") >>> e = Equation("2x = x + 2")
@ -118,7 +122,6 @@ class Equation(object):
... print(" = ".join([str(j) for j in i])) ... print(" = ".join([str(j) for j in i]))
2 x = x + 2 2 x = x + 2
2 x - x = x + 2 - x 2 x - x = x + 2 - x
2 x - x = x + 2 - x
( 2 - 1 ) x = x - x + 2 ( 2 - 1 ) x = x - x + 2
x = ( 1 - 1 ) x + 2 x = ( 1 - 1 ) x + 2
x = 2 x = 2
@ -126,7 +129,7 @@ class Equation(object):
>>> for i in e.solve(): >>> for i in e.solve():
... print(" = ".join([str(j) for j in i])) ... print(" = ".join([str(j) for j in i]))
2 x = 1 2 x = 1
2 x \times 2 = 1 \times 2 \frac{ 2 x }{ 2 } = \frac{ 1 }{ 2 }
\frac{ 2 }{ 2 } x = \frac{ 1 }{ 2 } \frac{ 2 }{ 2 } x = \frac{ 1 }{ 2 }
x = \frac{ 1 }{ 2 } x = \frac{ 1 }{ 2 }
>>> e = Equation("2x + 1 = 4x + 2") >>> e = Equation("2x + 1 = 4x + 2")
@ -134,16 +137,13 @@ class Equation(object):
... print(" = ".join([str(j) for j in i])) ... print(" = ".join([str(j) for j in i]))
2 x + 1 = 4 x + 2 2 x + 1 = 4 x + 2
2 x + 1 - 1 = 4 x + 2 - 1 2 x + 1 - 1 = 4 x + 2 - 1
2 x + 1 - 1 = 4 x + 2 - 1
2 x + 1 - 1 = 4 x + 2 - 1
2 x = 4 x + 1 2 x = 4 x + 1
2 x - 4 x = 4 x + 1 - 4 x 2 x - 4 x = 4 x + 1 - 4 x
2 x - 4 x = 4 x + 1 - 4 x
( 2 - 4 ) x = 4 x - 4 x + 1 ( 2 - 4 ) x = 4 x - 4 x + 1
-2 x = ( 4 - 4 ) x + 1 -2 x = ( 4 - 4 ) x + 1
-2 x = 1 -2 x = 1
-2 x \times ( -2 ) = 1 \times ( -2 ) \frac{ -2 x }{ -2 } = \frac{ 1 }{ -2 }
\frac{ -2 }{ -2 } x = \frac{ 1 }{ -2 } \frac{ -2 }{ -2 } x = \frac{ -1 }{ 2 }
x = \frac{ -1 }{ 2 } x = \frac{ -1 }{ 2 }
>>> e = Equation("2x + 3x + 1 = 4x + 2") >>> e = Equation("2x + 3x + 1 = 4x + 2")
>>> for i in e.solve(): >>> for i in e.solve():
@ -152,11 +152,8 @@ class Equation(object):
( 2 + 3 ) x + 1 = 4 x + 2 ( 2 + 3 ) x + 1 = 4 x + 2
5 x + 1 = 4 x + 2 5 x + 1 = 4 x + 2
5 x + 1 - 1 = 4 x + 2 - 1 5 x + 1 - 1 = 4 x + 2 - 1
5 x + 1 - 1 = 4 x + 2 - 1
5 x + 1 - 1 = 4 x + 2 - 1
5 x = 4 x + 1 5 x = 4 x + 1
5 x - 4 x = 4 x + 1 - 4 x 5 x - 4 x = 4 x + 1 - 4 x
5 x - 4 x = 4 x + 1 - 4 x
( 5 - 4 ) x = 4 x - 4 x + 1 ( 5 - 4 ) x = 4 x - 4 x + 1
x = ( 4 - 4 ) x + 1 x = ( 4 - 4 ) x + 1
x = 1 x = 1

8
pymath/calculus/step.py
View File

@ -74,7 +74,13 @@ class Step(Renderable):
if self.postfix_tokens == other.postfix_tokens: if self.postfix_tokens == other.postfix_tokens:
return True return True
except AttributeError: except AttributeError:
return False pass
try:
if str(self).replace(' ', '') == str(other).replace(' ',''):
return True
except TypeError:
pass
return False return False