Import work from year 2014-2015
This commit is contained in:
2057
1er_STMG/DS/DS_0410/Bilan/Bilan DS_0410.ipynb
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1er_STMG/DS/DS_0410/Bilan/Bilan DS_0410.ipynb
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1er_STMG/DS/DS_0410/Bilan/bilan.pdf
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1er_STMG/DS/DS_0410/Bilan/bilan.pdf
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1er_STMG/DS/DS_0410/Bilan/bilan.tex
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1er_STMG/DS/DS_0410/Bilan/bilan.tex
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1er_STMG/DS/DS_0410/Bilan/texenv.py
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1er_STMG/DS/DS_0410/Bilan/texenv.py
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#!/usr/bin/env python
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# encoding: utf-8
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import jinja2, os
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# Definition of jinja syntax for latex
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texenv = jinja2.Environment(
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block_start_string = '\Block{',
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# Gros WTF!! Si on le met en maj ça ne marche pas alors que c'est en maj dans le template...
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block_end_string = '}',
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variable_start_string = '\Var{',
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variable_end_string = '}',
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loader = jinja2.FileSystemLoader(os.path.abspath('.')),
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extensions = ['jinja2.ext.do']
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)
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# Filters
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if __name__ == '__main__':
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from pymath.expression import Expression
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exp = Expression("2/4 + 18")
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print(do_calculus(exp.simplify()))
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# -----------------------------
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# Reglages pour 'vim'
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# vim:set autoindent expandtab tabstop=4 shiftwidth=4:
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# cursor: 16 del
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1er_STMG/DS/DS_0410/Bilan/tpl_bilan.tex
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1er_STMG/DS/DS_0410/Bilan/tpl_bilan.tex
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\documentclass{/media/documents/Cours/Prof/Enseignements/Archive/2014-2015/tools/style/classBilan}
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\usepackage{/media/documents/Cours/Prof/Enseignements/Archive/2014-2015/2014_2015}
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\usepackage{multicol}
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% Title Page
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\titre{DS 6}
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% \seconde \premiereS \PSTMG \TSTMG
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\classe{\PSTMG}
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\date{10 avril 2015}
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\begin{document}
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\Block{for (name, notes) in eleves.iterrows()}
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\maketitle
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\begin{minipage}{0.5\linewidth}
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\large
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\Var{name}
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\end{minipage}
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\begin{minipage}{0.3\linewidth}
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\begin{flushright}
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\Large \Var{notes[ds_name]} / \Var{barem.DS_0410[0]}
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\end{flushright}
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\end{minipage}
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\vfill
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\fbox{%
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\begin{minipage}{0.9\linewidth}
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\hfill
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\vspace{3cm}
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\end{minipage}
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}
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\vfill
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\scriptsize
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\begin{multicols}{2}
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\begin{tabular}{|p{3cm}|c|c|}
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\hline
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\rowcolor{highlightbg} Exercices & Réussite & Barème \\
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\hline
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\Block{for question in barem.T[1:7].T}
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\Var{question} & \Var{notes[question]} & \Var{barem[question][0]} \\
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\hline
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\Block{endfor}
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\end{tabular}
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\begin{tabular}{|p{3cm}|c|c|}
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\hline
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\rowcolor{highlightbg} Exercices & Réussite & Barème \\
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\hline
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\Block{for question in barem.T[7:].T}
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\Var{question} & \Var{notes[question]} & \Var{barem[question][0]} \\
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\hline
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\Block{endfor}
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\end{tabular}
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\end{multicols}
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%\begin{tabular}{|p{2cm}|p{2cm}|p{2cm}|p{2cm}|p{2cm}|}
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% \hline
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% Pas de réponse & Faux & Peu juste & Partiellement juste & Juste \\
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% \hline
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% \NoRep & \RepZ & \RepU & \RepD & \RepT \\
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% \hline
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%\end{tabular}
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\normalsize
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\pagebreak
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\Block{endfor}
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "master"
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%%% End:
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1er_STMG/DS/DS_0410/DS_0410.pdf
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1er_STMG/DS/DS_0410/DS_0410.pdf
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1er_STMG/DS/DS_0410/DS_0410.tex
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1er_STMG/DS/DS_0410/DS_0410.tex
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\documentclass[a4paper,10pt, table]{/media/documents/Cours/Prof/Enseignements/Archive/2014-2015/tools/style/classDS}
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\usepackage{/media/documents/Cours/Prof/Enseignements/Archive/2014-2015/2014_2015}
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\usepackage{multicol}
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% Title Page
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\titre{6}
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% \seconde \premiereS \PSTMG \TSTMG
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\classe{\PSTMG}
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\date{10 avril 2015}
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%\duree{1 heure}
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%\sujet{%{{infos.subj%}}}
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% DS DSCorr DM DMCorr Corr
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\typedoc{DS}
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\begin{document}
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\maketitle
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Le barème est donné à titre indicatif, il pourra être modifié.
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\begin{questions}
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\vfill
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\question[4]
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\begin{parts}
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\part Tracer la représentation graphique d'une fonction qui a le tableau de variations suivant
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\begin{center}
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\begin{tikzpicture}
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\tkzTabInit[espcl=2]{$x$/1,$f(x)$/1}{-3, -2, 0, 1, 2}
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\tkzTabVar{-/{1}, +/{2}, -/{-3}, +/{0}, -/{-3}}
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\end{tikzpicture}
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\end{center}
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\part Résoudre l'inéquation suivante
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\begin{align*}
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3x + 2 &> -5x - 4
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\end{align*}
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\end{parts}
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\vfill
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\question[10]
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% Annale Bac STMG Antilles 2014 exo 3
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On s'intéresse à la propagation d'une maladie dans une ville de 130000 habitants. La fonction $f$ définie sur l'intervalle $\intFF{0}{40}$ par
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\begin{align*}
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f(x) &= -30t^2 + 1260t + 4000
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\end{align*}
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modélise le nombre de personnes touchées par la maladie au bout de $t$ jours de suivi de la propagation.
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\begin{parts}
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\part \textit{On donne en annexe la courbe représentative de la fonction $f$. Répondre aux questions ci-dessous par lecture graphique. Les résultats seronts justifés en commentant le travail réalisé sur le graphique et en y laissant les traits de construction.}
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\begin{subparts}
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% 1
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\subpart Déterminer le nombre de personnes touchées par la maladie au bout de 15 jours de suivi de la propagation.
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% 1
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\subpart Le conseil municipal a décidé de fermer les crèches de la ville lorsque plus de 10\% de la population est touchée par la maladie. Justifier qu'à partir de 13000 personnes contaminée, le conseil municipal ferme les crèches.
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% 1
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\subpart Pendant combien de jours les crèches ont-elles été fermée?
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% 1
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\subpart Combien de personnes, au maximum, on été touchée par la maladie?
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\end{subparts}
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\part
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\begin{subparts}
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% 1
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\subpart Déterminer,pour tout réel $t$ de l'intervalle $\intFF{0}{40}$, l'expression de $f'(t)$, où $f'$ désigne la fonction dérivée de la fonction $f$.
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% 2
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\subpart Étudier le signe de $f'(t)$ pour $t$ variant dans l'intervalle $\intFF{0}{40}$. En déduire le tableau de variations de la fonction $f$.
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% 1
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\subpart Au bout de combien de jours de suivi de la propagation le nombre de personnes touchées par la maladie est-il maximal?\\
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Combien y a-t-il alors de personnes touchées?
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\end{subparts}
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\end{parts}
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\vfill
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\pagebreak
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\question[6]
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\begin{center}
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\begin{itshape}
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Cet exercice est une questionnaire à choix multiplies (QCM).
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Pour chaque question, une seule des quatre réponses proposées est correcte.
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Indiquer sur la copie le numéro de la question ainsi que la réponse choisie. Aucune justification n'est demandée.
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Une réponse juste apporte 1,5point, une réponse fausse ou l'absence de réponse ne rapport ni n'enlève de points.
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\end{itshape}
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\end{center}
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\begin{parts}
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\part Quelle est la fonction dérivée de $f(x) = 5x + 0.3x - 12x^2$?
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\begin{multicols}{4}
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\begin{subparts}
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\subpart $f'(x) = 10x + 0.3$
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\subpart $f'(x) = -24x + 0.3$
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\subpart $f'(x) = 5x + 0.6$
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\subpart $f'(x) = -12x^2$
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\end{subparts}
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\end{multicols}
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\part Soit $g(x) = -0,1x(x + 4)(2x - 6)$ . Quelle est sa représentation graphique?
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\begin{multicols}{2}
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\begin{subparts}
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\subpart
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\begin{tikzpicture}[scale=0.2]
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\repereNoGrid{-10}{10}{-10}{10}
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\clip (-10,-10) rectangle (10,10);
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\draw[very thick, color=red] plot (\x, {-0.1*\x*(\x+4)*(2*\x-6)});
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%\draw[very thick, domain=0.2:4.2, color = red] plot (\x, {1/\x});
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\end{tikzpicture}
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\subpart
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\begin{tikzpicture}[scale=0.2]
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\repereNoGrid{-10}{10}{-10}{10}
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\clip (-10,-10) rectangle (10,10);
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\draw[very thick, color=red] plot (\x, {0.1*\x*(\x+4)*(2*\x-6)});
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%\draw[very thick, domain=0.2:4.2, color = red] plot (\x, {1/\x});
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\end{tikzpicture}
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\subpart
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\begin{tikzpicture}[scale=0.2]
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\repereNoGrid{-10}{10}{-10}{10}
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\clip (-10,-10) rectangle (10,10);
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\draw[very thick, color=red, domain=-10:10] plot (\x, {0.2*(\x+4)*(\x-3)});
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%\draw[very thick, domain=0.2:4.2, color = red] plot (\x, {1/\x});
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\end{tikzpicture}
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\subpart
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\begin{tikzpicture}[scale=0.2]
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\repereNoGrid{-10}{10}{-10}{10}
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\clip (-10,-10) rectangle (10,10);
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\draw[very thick, color=red] plot (\x, {-0.1*\x*(\x+9)*(2*\x-6)});
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%\draw[very thick, domain=0.2:4.2, color = red] plot (\x, {1/\x});
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\end{tikzpicture}
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\end{subparts}
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\end{multicols}
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\part Soit $h(x) = x^3$ . Quelle est son tableau de variation?
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\begin{subparts}
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\subpart
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\begin{center}
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\begin{tikzpicture}
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\tkzTabInit[espcl=2]{$x$/1,$x^3$/1}{$-\infty$, $+\infty$}
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\tkzTabVar{-/{}, +/{}}
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\end{tikzpicture}
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\end{center}
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\subpart
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\begin{center}
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\begin{tikzpicture}
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\tkzTabInit[espcl=2]{$x$/1,$x^3$/1}{$-\infty$,-1, 1, $+\infty$}
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\tkzTabVar{-/{}, +/{1}, -/{-1}, +/{}}
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\end{tikzpicture}
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\end{center}
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\subpart
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\begin{center}
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\begin{tikzpicture}
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\tkzTabInit[espcl=2]{$x$/1,$x^3$/1}{$-\infty$,-1, $+\infty$}
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\tkzTabVar{-/{}, +/{0}, -/{}}
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\end{tikzpicture}
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\end{center}
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\end{subparts}
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\part Quelle formule doit-on entrer dans la case \texttt{B2} puis étirer vers la droite pour calculer les valeurs de $g(x) = 3x^2 - 2x + 1$?
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\begin{center}
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\includegraphics[scale=0.6]{./fig/tableur}
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\end{center}
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\begin{multicols}{2}
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\begin{subparts}
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\subpart \Ovalbox{\verb|=3*B2^2 - 2*B2 + 1|}
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\subpart \Ovalbox{\verb|=3*(-2)^2 - 2*(-2) + 1|}
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\subpart \Ovalbox{\verb|=3*A2^2 - 2*A2 + 1|}
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\subpart \Ovalbox{\verb|=3*-2^2 - 2*-2 + 1|}
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\end{subparts}
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\end{multicols}
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\end{parts}
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\pagebreak
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\begin{center}
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\Large \textbf{Annexe} \normalsize
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\end{center}
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\vfill
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\Large\textbf{Nom et Prénom}
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\normalsize
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\vfill
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\begin{tikzpicture}[scale=1.5]
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\tkzInit[xmin=0,xmax=40,
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ymin=0,ymax=17500,
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xstep=5,ystep=2500]
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\tkzAxeX[thick, poslabel=right,label=]
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\tkzAxeY[thick, poslabel=above,label=]
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\tkzDrawX[label={\textit{Nombre de jours}},below= -12pt]
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\tkzDrawY[label={\textit{Nombre de personnes touchées}}, below=-10pt]
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\tkzGrid
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\tkzFct[domain=0:40,color=blue, very thick]{-30*\x*\x + 1260*\x+4000}
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\end{tikzpicture}
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\vfill
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\end{questions}
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "master"
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||||
%%% End:
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||||
|
2
1er_STMG/DS/DS_0410/DS_0410.tkzfct.gnuplot
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1er_STMG/DS/DS_0410/DS_0410.tkzfct.gnuplot
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set table "DS_0410.tkzfct.table"; set format "%.5f"
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set samples 200.0; plot [x=0:8.000000000000000000] (-30*(x*5)*(x*5)+ 1260*(x*5)+4000)/2500
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1er_STMG/DS/DS_0410/DS_0410.tkzfct.table
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1er_STMG/DS/DS_0410/DS_0410.tkzfct.table
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# Curve 0 of 1, 200 points
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# Curve title: "(-30*(x*5)*(x*5)+ 1260*(x*5)+4000)/2500"
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# x y type
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0.00000 1.60000 i
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0.04020 1.70082 i
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0.08040 1.80067 i
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0.12060 1.89956 i
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0.16080 1.99747 i
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0.20101 2.09441 i
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0.24121 2.19039 i
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0.28141 2.28539 i
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0.32161 2.37942 i
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0.36181 2.47249 i
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0.40201 2.56458 i
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0.44221 2.65571 i
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0.48241 2.74586 i
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0.52261 2.83505 i
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0.56281 2.92326 i
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0.60302 3.01051 i
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0.64322 3.09679 i
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0.68342 3.18209 i
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0.72362 3.26643 i
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0.76382 3.34980 i
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0.80402 3.43220 i
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0.84422 3.51362 i
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0.88442 3.59408 i
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0.92462 3.67357 i
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0.96482 3.75209 i
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1.00503 3.82964 i
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1.04523 3.90622 i
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1.08543 3.98183 i
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1.12563 4.05647 i
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1.16583 4.13014 i
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1.20603 4.20284 i
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1.24623 4.27457 i
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1.28643 4.34534 i
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1.32663 4.41513 i
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1.36683 4.48395 i
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1.40704 4.55180 i
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1.44724 4.61869 i
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1.48744 4.68460 i
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1.52764 4.74954 i
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1.56784 4.81352 i
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1.60804 4.87652 i
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1.64824 4.93856 i
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1.68844 4.99962 i
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1.72864 5.05972 i
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1.76884 5.11884 i
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1.80905 5.17700 i
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1.84925 5.23419 i
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1.88945 5.29040 i
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1.92965 5.34565 i
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1.96985 5.39993 i
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2.01005 5.45324 i
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2.05025 5.50557 i
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2.09045 5.55694 i
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2.13065 5.60734 i
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2.17085 5.65677 i
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2.21106 5.70523 i
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2.25126 5.75272 i
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2.29146 5.79924 i
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2.33166 5.84479 i
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2.37186 5.88937 i
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2.41206 5.93298 i
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2.45226 5.97562 i
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2.49246 6.01729 i
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2.53266 6.05800 i
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2.57286 6.09773 i
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2.61307 6.13649 i
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2.65327 6.17428 i
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2.69347 6.21111 i
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2.73367 6.24696 i
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2.77387 6.28185 i
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2.81407 6.31576 i
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2.85427 6.34870 i
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2.89447 6.38068 i
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2.93467 6.41168 i
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2.97487 6.44172 i
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3.01508 6.47079 i
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3.05528 6.49888 i
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3.09548 6.52601 i
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3.13568 6.55217 i
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BIN
1er_STMG/DS/DS_0410/fig/tableur.png
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1er_STMG/DS/DS_0410/fig/tableur.png
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Binary file not shown.
After Width: | Height: | Size: 12 KiB |
17
1er_STMG/DS/DS_0410/index.rst
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17
1er_STMG/DS/DS_0410/index.rst
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|
||||
Notes sur DS_0410
|
||||
#################
|
||||
|
||||
:date: 2015-07-01
|
||||
:modified: 2015-07-01
|
||||
:tags: DS, Fonctions, Dérivation
|
||||
:category: 1er_STMG
|
||||
:authors: Benjamin Bertrand
|
||||
:summary: Pas de résumé, note créée automatiquement parce que je ne l'avais pas bien fait...
|
||||
|
||||
|
||||
|
||||
`Lien vers DS_0410.pdf <DS_0410.pdf>`_
|
||||
|
||||
`Lien vers DS_0410.tex <DS_0410.tex>`_
|
||||
|
||||
`Lien vers fig/tableur.png <fig/tableur.png>`_
|
Reference in New Issue
Block a user