Import work from year 2014-2015
This commit is contained in:
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2nd/DS/DS_1212/Competences.pdf
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2nd/DS/DS_1212/Competences.pdf
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2nd/DS/DS_1212/Competences.tex
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2nd/DS/DS_1212/Competences.tex
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\documentclass{/media/documents/Cours/Prof/Enseignements/2014-2015/tools/style/classConn}
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% Title Page
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\title{}
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\author{}
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\date{}
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\begin{document}
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\begin{multicols}{2}
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Nom - Prénom - Classe:
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~\\[1cm]
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\textbf{Note:} \hfill {\Large /20}
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~\\[1cm]
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\textbf{Commentaires:} \\[4cm]
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\textbf{Compétences:}
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%\begin{competences}
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% \competence Dessin en 3D
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% \competence Lecture graphique
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% \competence Lecture tableau de varation
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% \competence Écriture mathématique
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%\end{competences}
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\vfill
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\hspace{-1cm}
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\begin{tabular}{|p{5cm}|*{3}{c|}}
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\hline
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Compétences & Non aquis & Cours d'aquisition & Aquis \\
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\hline
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Dessin en 3D &&&\\
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\hline
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Lecture graphique &&&\\
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\hline
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Lecture tableau de variations &&&\\
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\hline
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Écriture mathématique &&&\\
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\hline
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\end{tabular}
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\vfill
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\columnbreak
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Nom - Prénom - Classe:
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~\\[1cm]
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\textbf{Note:} \hfill {\Large /20}
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~\\[1cm]
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\textbf{Commentaires:} \\[4cm]
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\textbf{Compétences:}
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%\begin{competences}
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% \competence Dessin en 3D
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% \competence Lecture graphique
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% \competence Lecture tableau de varation
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% \competence Écriture mathématique
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%\end{competences}
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\vfill
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\hspace{-1cm}
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\begin{tabular}{|p{5cm}|*{3}{c|}}
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\hline
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Compétences & Non aquis & Cours d'aquisition & Aquis \\
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\hline
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Dessin en 3D &&&\\
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\hline
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Lecture graphique &&&\\
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\hline
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Lecture tableau de variations &&&\\
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\hline
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Écriture mathématique &&&\\
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\hline
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\end{tabular}
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\vfill
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\end{multicols}
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "master"
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%%% End:
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2nd/DS/DS_1212/DS_1212.pdf
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2nd/DS/DS_1212/DS_1212.pdf
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2nd/DS/DS_1212/DS_1212.tex
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\documentclass[a4paper,10pt, table]{/media/documents/Cours/Prof/Enseignements/2014-2015/tools/style/classDS}
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\usepackage{/media/documents/Cours/Prof/Enseignements/2014-2015/2014_2015}
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\usepackage{tkz-tab}
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\usepackage{tkz-fct}
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% Title Page
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\titre{DS 4}
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% \seconde \premiereS \PSTMG \TSTMG
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\classe{\seconde}
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\date{1é décembre 2014}
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%\duree{1 heure}
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%\sujet{%{{infos.subj%}}}
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% DS DSCorr DM DMCorr Corr
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\typedoc{DS}
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\printanswers
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\begin{document}
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\maketitle
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Le barème est donné à titre indicatif, il pourra être modifié.
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\begin{questions}
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\vfill
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\question[5]
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\begin{parts}
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\part Quel est le nom de la figure suivante. Quelles sont les faces visibles?
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\begin{center}
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\includegraphics[scale=0.2]{./fig/pyramid.png}
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\end{center}
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\begin{solution}
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La figure est un pyramide. Les faces visibles sont les faces $BFC$ et $CFD$.
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\end{solution}
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\part Vous répondrez aux questions suivantes à partir du pavé droit ci-dessous.
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\begin{minipage}{0.4\textwidth}
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\includegraphics[scale=0.3]{./fig/paveDroit}
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\end{minipage}
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\begin{minipage}{0.6\textwidth}
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\begin{subparts}
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\subpart Dessiner ce pavé droit de façon à ce que les faces $AEHD$, $EHCF$ et $DHGC$ soient visibles.
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\begin{solution}
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\includegraphics[scale=0.2]{./fig/paveDroit_corr}
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\end{solution}
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\subpart Calculer le volume de ce pavé droit.
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\begin{solution}
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Volume du pavé
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\begin{eqnarray*}
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V & = & 5\times3\times4 = 60
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\end{eqnarray*}
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\end{solution}
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\subpart Calculer la longueur $AC$.
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\begin{solution}
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Calcul de la longueur $AC$:
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Comme $ABC$ est un triangle rectangle en $B$ d'après le théorème de Pythagore, on a
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\begin{eqnarray*}
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AC^2 & = & AB^2 + BC^2\\
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AC^2 &=& 5^2 + 3^2\\
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AC^2 &=& 25 + 9 \\
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AC^2 &=& 34\\
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AC &=& \sqrt{34} \approx 5,8
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\end{eqnarray*}
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$AC$ mesure environ 5,8cm.
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\end{solution}
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\end{subparts}
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\end{minipage}
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\end{parts}
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\vfill
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\question[5]
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\begin{center}
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\begin{tikzpicture}[scale=0.5]
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\repere{-6}{6}{-6}{6}
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\draw[very thick, color=red] plot [smooth,tension=0.5, mark=*] coordinates{(-4, -4) (-3.5, -3) (-3, 0) (-2, 1) (-1, 0) (0, -3) (1, 0) (2, -3) (2.5,0) (3, 2) (4, 3)};
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\draw (4,3) node[above right] {$\mathcal{C}_f$};
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\end{tikzpicture}
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\end{center}
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\begin{parts}
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\part Tracer le tableau de variation de le fonction représentée sur le graphique.
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\begin{solution}
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\begin{tikzpicture}
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\tkzTabInit[espcl=2]{$x$/1,$f(x)$/1}{-4, -2, 0, 1, 2, 4}
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\tkzTabVar{-/{-4}, +/{1}, -/{-3}, +/{0}, -/{-3}, +/{3}}
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\end{tikzpicture}
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\end{solution}
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\part Sur quels intervalles cette fonction est-elle décroissantes?
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\begin{solution}
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La fonction $f$ est décroissante sur l'intervalle $\intFF{-2}{0}$ et $\intFF{1}{2}$.
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\end{solution}
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\part Quel est le minimum de la fonction sur l'intervalle $\intFF{-1}{3}$?
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\begin{solution}
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Sur l'intevalle $\intFF{-1}{3}$, le minimum de $f$ est -3, il est atteind pour $x = 0$ ou $x = 2$
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\end{solution}
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\part À partir de ce graphique, résoudre l'équation $f(x) = -3$
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\begin{solution}
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Les solutions de l'équation $f(x) = -3$ sont $x = -3,5$, $x = 0$ et $x = 2$.
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\end{solution}
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\end{parts}
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\vfill
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\question[5]
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\begin{tikzpicture}
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\tkzTabInit[]{$x$/1,$g(x)$/1}{$-3$, $-0.5$, $0$,$-1$,$+\infty$}
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\tkzTabVar{+/{2}, -/{-3}, +/{0}, -/{1}, +/}
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\end{tikzpicture}
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\begin{parts}
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\part Quel est l'intervalle de définition de la fonction $g$?
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\begin{solution}
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L'intervalle de définition de $g$ est $\intFF{-3}{+\infty}$.
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\end{solution}
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\part Sur quels intervalles cette fonction est-elle décroissantes?
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\begin{solution}
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La fonction $g$ est décroissante sur les intervalles $\intFF{-3}{-0,5}$ et $\intFF{0}{1}$.
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\end{solution}
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\part Quels est le minimum de cette fonction sur l'intervalle $\intFF{-3}{1}$?
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\begin{solution}
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Sur l'intervalle $\intFF{-3}{1}$ le minimum de $g$ est -3, il est atteind pour $x=-0,5$.
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\end{solution}
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\part Tracer une fonction qui a ce tableau de variation.
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\begin{solution}
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Voici une fonction possible.
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\begin{center}
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\begin{tikzpicture}[scale=0.7]
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\repere{-4}{4}{-4}{5}
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\draw[very thick, color=red] plot [smooth,tension=0.2, mark=*] coordinates{(-3, 2) (-0.5, -3) (0, 0) (1, -1) (4, 5) };
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\draw (4,5) node[above right] {$\mathcal{C}_g$};
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\end{tikzpicture}
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\end{center}
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\end{solution}
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\part Quel est le plus grand de ces deux nombres $g(-2)$ et $g(-1)$?
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\begin{solution}
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Comme la fonction est décroissante sur $\intFF{-3}{-0,5}$ et que -2 et -1 sont dans cet intervalle.
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\begin{eqnarray*}
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-2 < -1 & \mbox{ implique } & f(-2) > f(-1)
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\end{eqnarray*}
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Donc $f(-2)$ est plus grand que $f(-1)$.
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\end{solution}
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\end{parts}
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\vfill
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\question[5]
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L'entreprise Cducosto produit des outils de bricolages.
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\begin{parts}
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\part Leur premier produit est un marteau. Voici le graphique représentant les bénéfices en fonction du nombre de marteau qu'elle produit et vend.
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\begin{center}
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\begin{tikzpicture}[scale=0.7]
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\tkzInit[xmin=0,xmax=150,
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ymin=-200,ymax=300,
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xstep=10,ystep=50]
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\tkzAxeX[thick, poslabel=right,label=]
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\tkzAxeY[thick, poslabel=above,label=]
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\tkzDrawX[label={\textit{Nombre de marteau}},below= -12pt]
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\tkzDrawY[label={\textit{Bénéfices}}, below=-10pt]
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\tkzGrid
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\tkzFct[domain=0:150,color=blue, very thick]{-0.05*\x*\x + 7.5*\x - 180}
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\end{tikzpicture}
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\end{center}
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\begin{subparts}
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\subpart Tracer le tableau de signe de cette fonction.
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\begin{solution}
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\begin{tikzpicture}
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\tkzTabInit[]{$x$/1,$g(x)$/1}{0, 30, 120, 150}
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\tkzTabLine{, -, z, +, z, -,}
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\end{tikzpicture}
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\end{solution}
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\subpart Sur quel intervalle doit-elle restreindre sa production pour que ses bénéfices soient positifs?
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\begin{solution}
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Pour que les bénéfices soient positifs , il faut que la production reste sur l'intervalle $\intFF{3}{120}$
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\end{solution}
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\end{subparts}
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\part Leur deuxième produit est une visseuse automatique. Le bénéfice liés à cet outil est donné par la fonction suivante:
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\begin{eqnarray*}
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f:x & \mapsto & 2x - 3
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\end{eqnarray*}
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\begin{subparts}
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\subpart Tracer le tableau de signe de cette fonction.
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\begin{solution}
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On cherche là où la fonction $f$ est positive
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\begin{eqnarray*}
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f(x) & > &0\\
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2x - 3 & > & 0 \\
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2x & > & 3 \\
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&& \mbox{2 est positif, on ne change}\\
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&& \mbox{le sens de l'inégalité}\\
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x &>& \frac{3}{2} = 1,5
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\end{eqnarray*}
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On ne déduit le tableau de signe (on commence le tableau en 0 car on ne peut pas produire un nombre négatif de visseuses)
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\begin{tikzpicture}
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\tkzTabInit[]{$x$/1,$f(x)$/1}{0, {1,5}, $+\infty$}
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\tkzTabLine{ ,-, z, +,}
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\end{tikzpicture}
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\end{solution}
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\subpart À partir de combien de visseuses l'entreprise fait-elle du bénéfice?
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\begin{solution}
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À partir de 2 visseuses l'entreprise fait des bénéfices (là où dans le tableau au dessus il y a un +)
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\end{solution}
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\subpart Tracer le tableau de variation de cette fonction.
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\begin{solution}
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$f$ est une fonction affine et $a = 2$ est positif. Donc $f$ est une fonction croissante
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\begin{tikzpicture}
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\tkzTabInit[espcl=2]{$x$/1,$f(x)$/1}{0, $+\infty$}
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\tkzTabVar{-/{}, +/{}}
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\end{tikzpicture}
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\end{solution}
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\end{subparts}
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\end{parts}
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\end{questions}
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\vfill
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "master"
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%%% End:
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2nd/DS/DS_1212/DS_1212.tkzfct.gnuplot
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set table "DS_1212.tkzfct.table"; set format "%.5f"
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set samples 200.0; plot [x=0:15.000000000000000000] (-0.05*(x*10)*(x*10)+ 7.5*(x*10)- 180)/50
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2nd/DS/DS_1212/DS_1212.tkzfct.table
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2nd/DS/DS_1212/DS_1212.tkzfct.table
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# Curve 0 of 1, 200 points
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# Curve title: "(-0.05*(x*10)*(x*10)+ 7.5*(x*10)- 180)/50"
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# x y type
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0.00000 -3.60000 i
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0.07538 -3.48750 i
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0.15075 -3.37614 i
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0.22613 -3.26592 i
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0.30151 -3.15683 i
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0.37688 -3.04888 i
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0.45226 -2.94206 i
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0.52764 -2.83638 i
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0.60302 -2.73184 i
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0.67839 -2.62843 i
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0.75377 -2.52616 i
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0.82915 -2.42503 i
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0.90452 -2.32503 i
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0.97990 -2.22617 i
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1.05528 -2.12845 i
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1.13065 -2.03186 i
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1.20603 -1.93641 i
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1.28141 -1.84209 i
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1.35678 -1.74891 i
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1.43216 -1.65687 i
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1.50754 -1.56596 i
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1.58291 -1.47619 i
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1.65829 -1.38756 i
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1.73367 -1.30006 i
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1.80905 -1.21370 i
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1.88442 -1.12847 i
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1.95980 -1.04438 i
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2.03518 -0.96143 i
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2.11055 -0.87961 i
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2.18593 -0.79893 i
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2.26131 -0.71939 i
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2.33668 -0.64098 i
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2.41206 -0.56371 i
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2.48744 -0.48758 i
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2.56281 -0.41258 i
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2.63819 -0.33872 i
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2.71357 -0.26599 i
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2.78894 -0.19440 i
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2.86432 -0.12395 i
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2.93970 -0.05463 i
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3.01508 0.01355 i
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3.09045 0.08059 i
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3.16583 0.14650 i
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3.24121 0.21127 i
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3.31658 0.27490 i
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3.39196 0.33740 i
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3.46734 0.39876 i
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3.54271 0.45899 i
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3.61809 0.51808 i
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3.69347 0.57603 i
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3.76884 0.63285 i
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3.84422 0.68853 i
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3.91960 0.74307 i
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3.99497 0.79648 i
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4.07035 0.84875 i
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4.14573 0.89989 i
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4.22111 0.94989 i
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4.29648 0.99875 i
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4.37186 1.04647 i
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4.44724 1.09306 i
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4.59799 1.18283 i
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4.74874 1.26806 i
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4.82412 1.30897 i
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4.89950 1.34874 i
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4.97487 1.38737 i
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5.05025 1.42487 i
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5.12563 1.46124 i
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5.20101 1.49646 i
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5.27638 1.53055 i
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5.35176 1.56351 i
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5.42714 1.59532 i
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5.50251 1.62600 i
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5.57789 1.65555 i
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5.65327 1.68396 i
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5.72864 1.71123 i
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5.80402 1.73737 i
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5.87940 1.76236 i
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5.95477 1.78623 i
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6.03015 1.80895 i
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6.10553 1.83054 i
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6.18090 1.85100 i
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6.25628 1.87032 i
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6.33166 1.88850 i
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6.40704 1.90554 i
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6.48241 1.92145 i
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6.55779 1.93622 i
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6.63317 1.94986 i
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29
2nd/DS/DS_1212/index.rst
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||||
Notes sur DS_1212
|
||||
#################
|
||||
|
||||
:date: 2015-07-01
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||||
:modified: 2015-07-01
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||||
:tags: DS, Géométrie 3D, Fonctions
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||||
:category: 2nd
|
||||
:authors: Benjamin Bertrand
|
||||
:summary: Pas de résumé, note créée automatiquement parce que je ne l'avais pas bien fait...
|
||||
|
||||
|
||||
|
||||
`Lien vers DS_1212.tex <DS_1212.tex>`_
|
||||
|
||||
`Lien vers DS_1212_sujet.pdf <DS_1212_sujet.pdf>`_
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|
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`Lien vers Competences.tex <Competences.tex>`_
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|
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`Lien vers Competences.pdf <Competences.pdf>`_
|
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|
||||
`Lien vers DS_1212.pdf <DS_1212.pdf>`_
|
||||
|
||||
`Lien vers fig/paveDroit.pdf <fig/paveDroit.pdf>`_
|
||||
|
||||
`Lien vers fig/pyramid.png <fig/pyramid.png>`_
|
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|
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`Lien vers fig/paveDroit_corr.pdf <fig/paveDroit_corr.pdf>`_
|
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|
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Pour ce devoir j'ai essayé aussi d'ajouter des compétences mais sans réitérer plus tard...
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Reference in New Issue
Block a user