Feat: dernière questions pour avoir du 2nd degré
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\begin{frame}{Calcul 2}
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\begin{frame}{Calcul 2}
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Calculer la quantité suivante
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Calculer la quantité suivante
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\[
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\[
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\int_3^6 2t^2 + \frac{1}{2}t \; \dt =
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\int_3^6 2t^2 + \frac{1}{2}t \; dt =
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\]
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\]
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\end{frame}
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\end{frame}
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@ -54,18 +54,11 @@
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\begin{frame}[fragile]{Calcul 4}
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\begin{frame}[fragile]{Calcul 4}
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\vfill
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\vfill
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\textbf{Trouver la bonne forme}
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Résoudre l'équation
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\vfill
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\vfill
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\[
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La fonction $f(x) = \ln(6x+1) + \ln(6x - 2) - 2\ln2$ est égale à
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x^2 + 2,8x - 0,6 = 0
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\]
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\begin{itemize}
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\item $\ln(9x^2 - 1)$
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\item $\ln(36x^2 - 1)$
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\item $\ln(12x - 4)$
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\end{itemize}
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\end{frame}
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\end{frame}
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\begin{frame}{Fin}
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\begin{frame}{Fin}
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