Feat: brouillon pour les exo techniques sur le calcul littéral
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\documentclass[a4paper,10pt]{article}
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\usepackage{myXsim}
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\author{Benjamin Bertrand}
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\title{Fraction Developpement Litteral - Cours}
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\date{2021-08-25}
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\pagestyle{empty}
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\begin{document}
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\maketitle
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\end{document}
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BIN
2nd/01_Fraction_Developpement_Litteral/4E_developper.pdf
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2nd/01_Fraction_Developpement_Litteral/4E_developper.pdf
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2nd/01_Fraction_Developpement_Litteral/4E_developper.tex
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2nd/01_Fraction_Developpement_Litteral/4E_developper.tex
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\documentclass[a4paper,10pt]{article}
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\usepackage{myXsim}
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\usepackage{fancybox}
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\author{Benjamin Bertrand}
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\title{Fraction, calcul littéral et developpment - Cours}
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\date{Octobre 2021}
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\DeclareExerciseCollection[step=4]{banque}
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\xsimsetup{collect}
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\pagestyle{empty}
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\begin{document}
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\input{exercises.tex}
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\printcollection{banque}
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\end{document}
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\collectexercises{banque}
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\begin{exercise}[subtitle={Programmes de calculs}, step={4}, origin={D'anciennes choses}, topics={ Fraction Developpement Litteral }, tags={ Fractions, Developpement }]
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\begin{exercise}[subtitle={<++>}, step={1}, origin={<++>}, topics={ Fraction Developpement Litteral }, tags={ Fractions, Developpement }]
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Voici 2 programmes de cacluls.
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<++>
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\medskip
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\Ovalbox{%
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\textbf{Programme A:} Choisir un nombre > Multiplier par 4 > Soustraire 1 > Ajouter le nombre de départ > Soustraire 2
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}
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\Ovalbox{%
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\textbf{Programme B:} Choisir un nombre > Multiplier par 5 > Enlever 3
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}
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\medskip
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Abdou pense "\textit{Ces 2 programmes donnent toujours le même résultat.}".
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Qu'en pensez vous?
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\end{exercise}
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\end{exercise}
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\begin{solution}
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\begin{exercise}[subtitle={Pyramide additive}, step={4}, origin={D'anciennes choses}, topics={ Fraction Developpement Litteral }, tags={ Fractions, Developpement }]
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<++>
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\begin{minipage}{0.5\linewidth}
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\end{solution}
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La pyramide ci-contre est une pyramide additive. C'est à dire que pour trouver le nombre d'une case, il faut faire la somme des deux cases en dessous. Si l'on met le même nombre dans les deux cases grisées, on peut alors calculer le contenu de la case du sommet.
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\collectexercisesstop{banque}
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\medskip
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Comment calculer le résultat du sommet quelque soit le nombre mis dans les deux cases colorées?
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\end{minipage}
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\begin{minipage}{0.45\linewidth}
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\flushright
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\begin{tikzpicture}
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\draw (4,5)--(6,5)--(6,4)--(4,4)--cycle;
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\draw (3,4)--(5,4)--(5,3)--(3,3)--cycle;
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\draw (5,4)--(7,4)--(7,3)--(5,3)--cycle;
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\draw (2,3)--(4,3)--(4,2)--(2,2)--cycle;
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\draw (4,3)--(6,3)--(6,2)--(4,2)--cycle;
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\draw (6,3)--(8,3)--(8,2)--(6,2)--cycle;
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\draw (1,2)--(3,2)--(3,1)--(1,1)--cycle;
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\draw (2,1.5) node{$3$};
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\draw [fill=highlightbg](3,2)--(5,2)--(5,1)--(3,1)--cycle;
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\draw [fill=highlightbg](5,2)--(7,2)--(7,1)--(5,1)--cycle;
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\draw (7,2)--(9,2)--(9,1)--(7,1)--cycle;
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\draw (8,1.5) node{$7$};
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\end{tikzpicture}
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\end{minipage}
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\end{exercise}
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