Feat: clean repository

bopytex/__init__.py

@@ -1,10 +1,6 @@
 #!/usr/bin/env python
 # encoding: utf-8
 
-
-#from .bopytex import subject_metadatas, crazy_feed, pdfjoin
-
-
 # -----------------------------
 # Reglages pour 'vim'
 # vim:set autoindent expandtab tabstop=4 shiftwidth=4:

bopytex/filters.py

@@ -1,33 +0,0 @@
-#!/usr/bin/env python
-# encoding: utf-8
-
-"""
-Custom filter for Bopytex
-"""
-
-__all__ = ["do_calculus"]
-
-def do_calculus(steps, name="A", sep="=", end="", joining=" \\\\ \n"):
-    """Display properly the calculus
-
-    Generate this form string:
-    "name & sep & a_step end joining"
-
-    :param steps: list of steps
-    :returns: latex string ready to be endbeded
-
-
-    """
-
-    ans = joining.join([
-        name + " & "
-        + sep + " & "
-        + str(s) + end for s in steps
-        ])
-    return ans
-
-
-# -----------------------------
-# Reglages pour 'vim'
-# vim:set autoindent expandtab tabstop=4 shiftwidth=4:
-# cursor: 16 del

bopytex/lib/pythagore.py

@@ -1,38 +0,0 @@
-#!/usr/bin/env python
-# encoding: utf-8
-
-from random import randint
-
-def pythagore_triplet(v_min = 1, v_max = 10):
-    """Random pythagore triplet generator
-
-    :param v_min: minimum in randint
-    :param v_max: max in randint
-    :returns: (a,b,c) such that a^2 + b^2 = c^2
-
-    """
-    u = randint(v_min,v_max)
-    v = randint(v_min,v_max)
-    while v == u:
-        v = randint(v_min,v_max)
-
-    u, v = max(u,v), min(u,v)
-
-    return (u**2-v**2 , 2*u*v, u**2 + v**2)
-
-if __name__ == '__main__':
-    print(pythagore_triplet())
-
-    for j in range(1,10):
-        for i in range(j,10):
-            print((i**2-j**2 , 2*i*j, i**2 + j**2))
-
-
-
-
-
-
-# -----------------------------
-# Reglages pour 'vim'
-# vim:set autoindent expandtab tabstop=4 shiftwidth=4:
-# cursor: 16 del 

bopytex/macros/poly2Deg.tex

@@ -1,33 +0,0 @@
-\Block{macro solveEquation(P)}
-
-    On commence par calculer le discriminant de $P(x) = \Var{P}$.
-    \begin{eqnarray*}
-        \Delta & = & b^2-4ac \\
-        \Var{P.delta.explain()|calculus(name="\\Delta")}
-    \end{eqnarray*}
-
-    \Block{if P.delta > 0}
-    comme $\Delta = \Var{P.delta} > 0$ donc $P$ a deux racines
-
-    \begin{eqnarray*}
-        x_1 & = & \frac{-b - \sqrt{\Delta}}{2a} =  \frac{\Var{-P.b} - \sqrt{\Var{P.delta}}}{2 \times \Var{P.a}} = \Var{P.roots()[0] } \\
-        x_2 & = & \frac{-b + \sqrt{\Delta}}{2a} =  \frac{\Var{-P.b} + \sqrt{\Var{P.delta}}}{2 \times \Var{P.a}} = \Var{P.roots()[1] }
-    \end{eqnarray*}
-
-    Les solutions de l'équation $\Var{P} = 0$ sont donc $\mathcal{S} = \left\{ \Var{P.roots()[0]}; \Var{P.roots()[1]} \right\}$
-
-    \Block{elif P.delta == 0}
-    Comme $\Delta = 0$ donc $P$ a une racine
-
-    \begin{eqnarray*}
-        x_1 = \frac{-b}{2a} = \frac{-\Var{P.b}}{2\times \Var{P.a}} = \Var{P.roots()[0]} \\
-    \end{eqnarray*}
-
-    La solution de $\Var{P} = 0$ est donc $\mathcal{S} = \left\{ \Var{P.roots()[0]}\right\}$
-
-    \Block{else}
-    Alors $\Delta = \Var{P.delta} < 0$ donc $P$ n'a pas de racine donc l'équation $\Var{P} = 0$ n'a pas de solution.
-
-    \Block{endif}
-
-\Block{endmacro}