122 lines
4.0 KiB
TeX
122 lines
4.0 KiB
TeX
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\documentclass[a4paper,12pt,landscape, twocolumn]{/media/documents/Cours/Prof/Enseignements/Archive/2013-2014/tools/style/classExo}
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\usepackage{multicol}
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% Title Page
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\title{Identités remarquables et équations- Exercices}
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\author{}
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\date{}
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\fancyhead[L]{Troisième}
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\fancyhead[C]{\Thetitle}
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\fancyhead[R]{\thepage}
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\begin{document}
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\thispagestyle{empty}
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\begin{Exo}
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\exo{Équations de degrés 1}
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\begin{center}
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\framebox{\parbox{0.4\textwidth}{
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Résoudre l'équation $3x + 5 = 0$.
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\begin{eqnarray*}
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3x + 5 = 0 & \hspace{1cm} & \mbox{On ajoute l'opposé de 5} \\
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3x + 5 \mathbf{+ (-5)} = \mathbf{-5} && \\
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3x = -5 & \hspace{1cm} & \mbox{On multiplie par l'inverse de 3} \\
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\mathbf{\frac{1}{3} \times }3x = \mathbf{ \frac{1}{3} \times }(-5) && \\
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x = \frac{-5}{3}
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\end{eqnarray*}
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La solution est $x = \frac{-5}{3}$.
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}}
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\end{center}
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\begin{enumerate}
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\item Résoudre l'équation $4x + 7 = 0$.
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\begin{eqnarray*}
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4x + 7 = 0 & \hspace{0.5cm} & \mbox{On ajoute l'opposé de \parbox{1cm}{\dotfill}} \\[0.5cm]
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4x + 7 + \parbox{1.5cm}{\dotfill}= \parbox{1.5cm}{\dotfill}&& \\[0.5cm]
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4x = \parbox{1cm}{\dotfill}& \hspace{0.5cm} & \mbox{On multiplie par l'inverse de \parbox{1cm}{\dotfill}} \\[0.5cm]
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\parbox{1.5cm}{\dotfill} \times 4x = \parbox{1.5cm}{\dotfill} \times \parbox{1cm}{\dotfill} && \\[0.5cm]
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x = \frac{\parbox{1cm}{\dotfill}}{\parbox{1cm}{\dotfill}}
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\end{eqnarray*}
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La solution est \parbox{2cm}{\dotfill}.
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\item Résoudre les équations suivantes
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\begin{multicols}{2}
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\begin{enumerate}
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\item $2x + 1 = 0$
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\item $6x + 12 = 0$
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\item $3x - 3 = 0$
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\item $8x - 4 = 0$
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\columnbreak
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\item $-6x - 3 = 0$
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\item $9 + 3x = 0$
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\item $5 + 3x = 0$
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\item $\frac{2}{3}x + 3 = 0$
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\end{enumerate}
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\end{multicols}
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\end{enumerate}
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\end{Exo}
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\eject
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\setcounter{exo}{0}
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\begin{Exo}
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\exo{Équations de degrés 1}
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\begin{center}
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\framebox{\parbox{0.4\textwidth}{
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Résoudre l'équation $3x + 5 = 0$.
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\begin{eqnarray*}
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3x + 5 = 0 & \hspace{1cm} & \mbox{On ajoute l'opposé de 5} \\
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3x + 5 \mathbf{+ (-5)} = \mathbf{-5} && \\
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3x = -5 & \hspace{1cm} & \mbox{On multiplie par l'inverse de 3} \\
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\mathbf{\frac{1}{3} \times }3x = \mathbf{ \frac{1}{3} \times }(-5) && \\
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x = \frac{-5}{3}
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\end{eqnarray*}
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La solution est $x = \frac{-5}{3}$.
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}}
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\end{center}
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\begin{enumerate}
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\item Résoudre l'équation $4x + 7 = 0$.
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\begin{eqnarray*}
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4x + 7 = 0 & \hspace{0.5cm} & \mbox{On ajoute l'opposé de \parbox{1cm}{\dotfill}} \\[0.5cm]
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4x + 7 + \parbox{1.5cm}{\dotfill}= \parbox{1.5cm}{\dotfill}&& \\[0.5cm]
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4x = \parbox{1cm}{\dotfill}& \hspace{0.5cm} & \mbox{On multiplie par l'inverse de \parbox{1cm}{\dotfill}} \\[0.5cm]
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\parbox{1.5cm}{\dotfill} \times 4x = \parbox{1.5cm}{\dotfill} \times \parbox{1cm}{\dotfill} && \\[0.5cm]
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x = \frac{\parbox{1cm}{\dotfill}}{\parbox{1cm}{\dotfill}}
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\end{eqnarray*}
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La solution est \parbox{2cm}{\dotfill}.
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\item Résoudre les équations suivantes
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\begin{multicols}{2}
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\begin{enumerate}
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\item $2x + 1 = 0$
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\item $6x + 12 = 0$
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\item $3x - 3 = 0$
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\item $8x - 4 = 0$
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\columnbreak
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\item $-6x - 3 = 0$
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\item $9 + 3x = 0$
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\item $5 + 3x = 0$
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\item $\frac{2}{3}x + 3 = 0$
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\end{enumerate}
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\end{multicols}
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\end{enumerate}
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\end{Exo}
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\eject
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\end{document}
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%%% Local Variables:
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%%% mode: latex
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%%% TeX-master: "master"
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%%% End:
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