Import work from year 2013-2014

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Benjamin Bertrand
2017-06-16 09:46:40 +03:00
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\documentclass[a4paper,10pt]{beamer}
\usepackage[utf8]{inputenc}
\usepackage[french]{babel}
\usepackage{graphicx}
\usepackage{thumbpdf}
\usepackage{wasysym}
\usepackage{ucs}
\usepackage{pgf,pgfarrows,pgfnodes,pgfautomata,pgfheaps,pgfshade}
\usepackage{verbatim}
\usepackage{subfig}
\usepackage{amssymb}
\usepackage{tikz}
\usepackage{enumerate}
\usepackage{array}
\renewcommand{\arraystretch}{3}
\setlength{\tabcolsep}{10pt}
\begin{document}
\begin{frame}{Opérations et inégalités.}
\begin{tabular}{|m{4cm}|*{4}{m{1cm}|}}
\hline
Inégalité & -3 & +4 & $\times 2$ & $\times (-1)$ \\
\hline
$4 \leq 7$ & & & &\\
\hline
$6 > 1$ & & & &\\
\hline
$4 \geq -1$ & & & &\\
\hline
Sens de l'inégalité changé? &&&& \\
\hline
\end{tabular}
\end{frame}
\end{document}

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Notes sur une activité autour des inéquations pour les 3e
#########################################################
:date: 2014-07-01
:modified: 2014-07-01
:tags: Nombres Calculs, Inequations
:category: 3e
:authors: Benjamin Bertrand
:summary: Pas de résumé, note créée automatiquement parce que je ne l'avais pas bien fait...
`Lien vers act_op_ineq.tex <act_op_ineq.tex>`_
`Lien vers act_op_ineq.pdf <act_op_ineq.pdf>`_

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Notes sur des fiches d'exercices autour des inéquations
#######################################################
:date: 2014-07-01
:modified: 2014-07-01
:tags: Nombres Calculs,Exo, Inequations
:category: 3e
:authors: Benjamin Bertrand
:summary: Pas de résumé, note créée automatiquement parce que je ne l'avais pas bien fait...
`Lien vers inequations_1.pdf <inequations_1.pdf>`_
`Lien vers inequations_1.tex <inequations_1.tex>`_
`Lien vers slideCorr_17p92.tex <slideCorr_17p92.tex>`_
`Lien vers inequations_3.pdf <inequations_3.pdf>`_
`Lien vers inequations_2.tex <inequations_2.tex>`_
`Lien vers inequations_3.tex <inequations_3.tex>`_
`Lien vers inequations_2.pdf <inequations_2.pdf>`_
`Lien vers slideCorr_17p92.pdf <slideCorr_17p92.pdf>`_
`Lien vers fig/axe.pdf <fig/axe.pdf>`_
`Lien vers fig/axe_1.pdf <fig/axe_1.pdf>`_
`Lien vers fig/axe_3.pdf <fig/axe_3.pdf>`_
`Lien vers fig/axe_5.pdf <fig/axe_5.pdf>`_
`Lien vers fig/axe_2.pdf <fig/axe_2.pdf>`_
`Lien vers fig/axe_4.pdf <fig/axe_4.pdf>`_

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\documentclass[a4paper,12pt,landscape, twocolumn]{/media/documents/Cours/Prof/Enseignements/Archive/2013-2014/tools/style/classExo}
\usepackage{multicol}
% Title Page
\title{Inéquations- Exercices}
\author{}
\date{}
\fancyhead[L]{Troisième}
\fancyhead[C]{\Thetitle}
\fancyhead[R]{\thepage}
\begin{document}
\thispagestyle{fancy}
\begin{Exo}
Traduire en français les expressions mathématiques suivantes
\begin{multicols}{2}
\begin{enumerate}
\item $5 \leq 9$
\item $23 \geq 9$
\item $x \leq 6$
\item $3 > x$
\columnbreak
\item $5x > 1$
\item $x < y$
\item $2x > 4x$
\item $4y \leq 9$
\end{enumerate}
\end{multicols}
\end{Exo}
\begin{Exo}
\begin{enumerate}
\item Dire si les phrases suivantes sont justes en justifiant.
\begin{itemize}
\item Si $x = 2$ alors $x \leq 4$.
\item Si $x = 2,32$ alors $x \geq 2$.
\item Si $x = 4$ alors $2x > 8$.
\item Si $x = 6$ alors $3x - 4 \geq 14$.
\item Si $x = 2$ alors $3x + 1 < 4x -1$.
\item Si $a = 1$ alors $\frac{1}{3}a \leq 0.5$.
\end{itemize}
\item Trouver une valeur de $x$ pour que les inéquations suivantes soient vraies.
\begin{multicols}{2}
\begin{enumerate}
\item $x \leq 9$
\item $23 \geq 9x$
\item $x \leq 6$
\item $3 > x$
\columnbreak
\item $5x > 1$
\item $x + 4 < 2$
\item $2x > 4x$
\item $4x \leq 9$
\end{enumerate}
\end{multicols}
\end{enumerate}
\end{Exo}
\eject
\begin{Exo}
\begin{enumerate}
\item Surligner les valeurs possibles pour $x$ dans les inéquations suivantes.
\begin{enumerate}
\item $x \geq 1$
\includegraphics[scale=0.4]{./fig/axe_1.pdf}
\item $x < 2$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x > -3$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 4$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x < 1$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\end{enumerate}
\item Écrire l'inéquation qui correspond au graphique.
\begin{enumerate}
\item
\includegraphics[scale=0.3]{./fig/axe_2.pdf} \parbox{2cm}{\dotfill}
\item
\includegraphics[scale=0.3]{./fig/axe_3.pdf} \parbox{2cm}{\dotfill}
\item
\includegraphics[scale=0.3]{./fig/axe_4.pdf} \parbox{2cm}{\dotfill}
\item
\includegraphics[scale=0.3]{./fig/axe_5.pdf} \parbox{2cm}{\dotfill}
\end{enumerate}
\end{enumerate}
\end{Exo}
\begin{Exo}
\exo{31p94}
\exo{30p94}
\end{Exo}
\end{document}
%%% Local Variables:
%%% mode: latex
%%% TeX-master: "master"
%%% End:

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\documentclass[a4paper,12pt,landscape, twocolumn]{/media/documents/Cours/Prof/Enseignements/Archive/2013-2014/tools/style/classExo}
\usepackage{multicol}
% Title Page
\title{Inéquations- Exercices}
\author{}
\date{}
\fancyhead[L]{Troisième}
\fancyhead[C]{\Thetitle}
\fancyhead[R]{\thepage}
\begin{document}
\thispagestyle{fancy}
\begin{Exo}
Surligner les valeurs possibles pour $x$ dans les inéquations suivantes.
\begin{enumerate}
\item $x \geq -1$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x < -2$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 3$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 5$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\end{enumerate}
\end{Exo}
\begin{Exo}
Donner trois valeurs possibles pour $x$ puis représenter graphiquement les solutions des inéquations suivantes.
\begin{enumerate}
\item $x + 3 \leq 6$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x - 1 \geq -2$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x + 10 \leq 5$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 6 - x$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\end{enumerate}
\end{Exo}
\eject
\setcounter{exo}{0}
\begin{Exo}
Surligner les valeurs possibles pour $x$ dans les inéquations suivantes.
\begin{enumerate}
\item $x \geq -1$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x < -2$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 3$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 5$
\includegraphics[scale=0.4]{./fig/axe.pdf}
\end{enumerate}
\end{Exo}
\begin{Exo}
Donner trois valeurs possibles pour $x$ puis représenter graphiquement les solutions des inéquations suivantes.
\begin{enumerate}
\item $x + 3 \leq 6$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x - 1 \geq -2$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x + 10 \leq 5$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\item $x \leq 6 - x$: \hspace{1cm} Valeurs possibles: \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}, \parbox{1cm}{\dotfill}
\includegraphics[scale=0.4]{./fig/axe.pdf}
\end{enumerate}
\end{Exo}
\end{document}
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\documentclass[a4paper,12pt,landscape, twocolumn]{/media/documents/Cours/Prof/Enseignements/Archive/2013-2014/tools/style/classExo}
%\usepackage{multicol}
\usepackage{tikz}
\usepackage{fancybox}
% Title Page
\title{Inéquations 3 - Exercices}
\author{}
\date{}
\fancyhead[L]{Troisième}
\fancyhead[C]{\Thetitle}
\fancyhead[R]{\thepage}
\begin{document}
\thispagestyle{fancy}
\begin{Exo}
\begin{center}
\framebox{\parbox{0.45\textwidth}{
Résoudre l'inéquation $3x + 5 > 0$ et représenter graphiquement les solutions.
\begin{eqnarray*}
3x + 5 > 0 & \hspace{1cm} & \mbox{On ajoute l'opposé de 5} \\
3x + 5 \mathbf{+ (-5)} > \mathbf{-5} && \\
3x > -5 & \hspace{1cm} & \mbox{On multiplie par l'inverse de 3 \colorbox{lightgray}{positif}} \\
\mathbf{\frac{1}{3} \times }3x > \mathbf{ \frac{1}{3} \times }(-5) && \mbox{On ne change pas le sens de l'inégalité}\\
x > \frac{-5}{3}
\end{eqnarray*}
La solution est $x > \frac{-5}{3}$.
\begin{tikzpicture}
\draw[->, very thick] (-5,0) -- (6,0);
\foreach \x in {-5,-4,...,5} {
\draw(\x,0) node[below] {\x} node {|};
}
\draw[color=red, line width = 5pt] ({-5/3}, 0) node[scale=2.5]{]} node[above left, scale = 1.3] {$\frac{-5}{3}$} -- (6,0);
\end{tikzpicture}
}}
\end{center}
\begin{center}
\framebox{\parbox{0.45\textwidth}{
Résoudre l'inéquation $-5x + 4 > 0$ et représenter graphiquement les solutions.
\begin{eqnarray*}
-5x + 4 > 0 & \hspace{1cm} & \mbox{On ajoute l'opposé de 4} \\
-5x + 4 \mathbf{+ (-4)} > \mathbf{-4} && \\
-5x > -4 & \hspace{1cm} & \mbox{On multiplie par l'inverse de -5 \colorbox{lightgray}{négatif}} \\
\mathbf{\frac{1}{-5} \times }-5x \colorbox{lightgray}{<} \mathbf{ \frac{1}{-5} \times }(-4) && \mbox{On a changé le sens de l'inégalité}\\
x < \frac{-4}{-5} = \frac{4}{5}
\end{eqnarray*}
La solution est $x < \frac{4}{5}$.
\begin{tikzpicture}
\draw[->, very thick] (-2,0) -- (6,0);
\foreach \x in {-2,-1,...,5} {
\draw(\x,0) node[below] {\x} node {|};
}
\draw[color=red, line width = 5pt] (-2,0) --({4/5}, 0)node[scale=2.5]{[} node[above right, scale = 1.3] {$\frac{4}{5}$} ;
\end{tikzpicture}
}}
\end{center}
\begin{enumerate}
\item Résoudre puis représenter les solutions de l'inéquation $4x + 7 > 0$.
\begin{eqnarray*}
4x + 7 > 0 & \hspace{0.5cm} & \mbox{On ajoute l'opposé de \parbox{1cm}{\dotfill}} \\[0.5cm]
4x + 7 + \parbox{1.5cm}{\dotfill}> \parbox{1.5cm}{\dotfill}&& \\[0.5cm]
4x > \parbox{1cm}{\dotfill}& \hspace{0.5cm} & \mbox{On multiplie par l'inverse de \parbox{1cm}{\dotfill}} \\[0.5cm]
\parbox{1.5cm}{\dotfill} \times 4x \ovalbox{\begin{minipage}{0.3cm}\hfill\vspace{0.5cm}\end{minipage}} \parbox{1.5cm}{\dotfill} \times \parbox{1cm}{\dotfill} && \mbox{On \parbox{2cm}{\dotfill} le sens de l'inégalité} \\[0.5cm]
x \ovalbox{\begin{minipage}{0.3cm}\hfill\vspace{0.5cm}\end{minipage}} \frac{\parbox{1cm}{\dotfill}}{\parbox{1cm}{\dotfill}}
\end{eqnarray*}
La solution est \parbox{2cm}{\dotfill}.
\\[0.5cm]
\begin{tikzpicture}
\draw[->, very thick] (-4,0) -- (6,0);
\foreach \x in {-4,-3,...,5} {
\draw(\x,0) node[below] {\x} node {|};
}
\end{tikzpicture}
\item Résoudre puis représenter les solutions des inéquations suivantes
\begin{enumerate}
\item $3x + 2 \geq 0$
\item $5x - 10 \leq 0$
\item $-3x + 9 > 0$
\item $-2 x - 6 < 0$
\item $3x + 4 > 7 $
\item $-5x - 8 \geq 2$
\end{enumerate}
\end{enumerate}
\end{Exo}
\end{document}
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\documentclass[a4paper,10pt]{beamer}
\usepackage[utf8]{inputenc}
\usepackage[french]{babel}
\usepackage{graphicx}
\usepackage{thumbpdf}
\usepackage{wasysym}
\usepackage{ucs}
\usepackage{pgf,pgfarrows,pgfnodes,pgfautomata,pgfheaps,pgfshade}
\usepackage{verbatim}
\usepackage{subfig}
\usepackage{amssymb}
\usepackage{tikz}
\usepackage{enumerate}
\begin{document}
\begin{frame}{Solution l'exercice 17 p 93}
\begin{enumerate}[a.]
\item $x + 7 < 12$ \hspace{2cm} Autre inéquation correspondante:
\begin{tikzpicture}
\draw[->, very thick] (-2.5,0) -- (7,0);
\foreach \x in {-2,-1,...,6} {
\draw(\x,0) node[below] {\x} node {+};
}
\end{tikzpicture}
\item $5 + x \leq -9$ \hspace{2cm} Autre inéquation correspondante:
\begin{tikzpicture}
\draw[->, very thick] (-17.5,0) -- (-8,0);
\foreach \x in {-17,-16,...,-9} {
\draw(\x,0) node[below] {\x} node {+};
}
\end{tikzpicture}
\item $t - 7 > 0$ \hspace{2cm} Autre inéquation correspondante:
\begin{tikzpicture}
\draw[->, very thick] (1.5,0) -- (10,0);
\foreach \x in {2,3,...,9} {
\draw(\x,0) node[below] {\x} node {+};
}
\end{tikzpicture}
\item $y + 1 \geq 1,5$ \hspace{2cm} Autre inéquation correspondante:
\begin{tikzpicture}
\draw[->, very thick] (-2.5,0) -- (7,0);
\foreach \x in {-2,-1,...,6} {
\draw(\x,0) node[below] {\x} node {+};
}
\end{tikzpicture}
\item $10 + x > -20$ \hspace{2cm} Autre inéquation correspondante:
\begin{tikzpicture}
\draw[->, very thick] (-6.5,0) -- (3.5,0);
\foreach \x in {-60,-50,...,30} {
\draw({\x/10},0) node[below] {\x} node {+};
}
\end{tikzpicture}
\item $t - 51 < -30$ \hspace{2cm} Autre inéquation correspondante:
\begin{tikzpicture}
\draw[->, very thick] (15.5,0) -- (25,0);
\foreach \x in {16,17,...,25} {
\draw(\x,0) node[below] {\x} node {+};
}
\end{tikzpicture}
\end{enumerate}
\end{frame}
\end{document}