Question flash pour les 1S

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Bertrand Benjamin 2018-09-12 09:19:46 +02:00
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\documentclass[a4paper,12pt]{classPres}
\usepackage{tkz-fct}
\author{}
\title{}
\date{}
\begin{document}
\begin{frame}{Questions flashs}
Développer l'expression
\[ A = -3(x+5)^2 - 7 \]
Mettre sous forme canonique
\[ B = x^2 - 6x - 7 \]
\end{frame}
\begin{frame}{Correction}
\begin{eqnarray*}
A &=& -3(x+5)^2 - 7 \\
&=& -3x^2 - 30x - 82
\end{eqnarray*}
\hline
\begin{eqnarray*}
B = x^2 - 6x - 7
\end{eqnarray*}
\[ \alpha = \frac{-b}{2a} = 3 \]
\[ \beta = -\frac{b^2-4ac}{4a} = -\frac{36+38}{4} = -16 \]
\begin{eqnarray*}
B &=& (x - 3)^2 - 16 \\
\end{eqnarray*}
\end{frame}
\end{document}