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Feat: change baseline

This commit is contained in:
Bertrand Benjamin 2020-08-26 13:21:19 +02:00
parent b2921741b4
commit 65f2a4c21c
2 changed files with 8 additions and 9 deletions
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tools/examples/shortcuts_settings.pdf
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tools/examples/shortcuts_settings.tex
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@ -170,7 +170,7 @@
\begin{multicols}{2} \begin{multicols}{2}
\begin{verbatim} \begin{verbatim}
\begin{tikzpicture}[baseline=(a.north), \begin{tikzpicture}[baseline=(current bounding box.south),
xscale=1, yscale=0.5] xscale=1, yscale=0.5]
\tkzInit[xmin=-5,xmax=5,xstep=1, \tkzInit[xmin=-5,xmax=5,xstep=1,
ymin=-5,ymax=5,ystep=1] ymin=-5,ymax=5,ystep=1]
@ -182,7 +182,7 @@
\end{verbatim} \end{verbatim}
\columnbreak \columnbreak
\begin{tikzpicture}[baseline=(a.north), \begin{tikzpicture}[baseline=(current bounding box.south),
xscale=1, yscale=0.5] xscale=1, yscale=0.5]
\tkzInit[xmin=-5,xmax=5,xstep=1, \tkzInit[xmin=-5,xmax=5,xstep=1,
ymin=-5,ymax=5,ystep=1] ymin=-5,ymax=5,ystep=1]
@ -198,7 +198,7 @@ Quand on change la valeur de \verb+xstep+, il faut replacer \verb+x+ par \verb+\
\begin{multicols}{2} \begin{multicols}{2}
\begin{verbatim} \begin{verbatim}
\begin{tikzpicture}[baseline=(a.north), \begin{tikzpicture}[baseline=(current bounding box.south),
xscale=0.5, yscale=0.4] xscale=0.5, yscale=0.4]
\tkzInit[xmin=-5,xmax=5,xstep=0.5, \tkzInit[xmin=-5,xmax=5,xstep=0.5,
ymin=-5,ymax=5,ystep=1] ymin=-5,ymax=5,ystep=1]
@ -209,7 +209,7 @@ Quand on change la valeur de \verb+xstep+, il faut replacer \verb+x+ par \verb+\
\end{tikzpicture} \end{tikzpicture}
\end{verbatim} \end{verbatim}
\columnbreak \columnbreak
\begin{tikzpicture}[baseline=(a.north), \begin{tikzpicture}[baseline=(current bounding box.south),
xscale=0.5, yscale=0.4] xscale=0.5, yscale=0.4]
\tkzInit[xmin=-5,xmax=5,xstep=0.5, \tkzInit[xmin=-5,xmax=5,xstep=0.5,
ymin=-5,ymax=5,ystep=1] ymin=-5,ymax=5,ystep=1]
@ -224,14 +224,14 @@ Quand on change la valeur de \verb+xstep+, il faut replacer \verb+x+ par \verb+\
\begin{multicols}{2} \begin{multicols}{2}
\begin{verbatim} \begin{verbatim}
\begin{tikzpicture}[baseline=(a.north)] \begin{tikzpicture}[baseline=(current bounding box.south)]
\tkzTabInit[lgt=2,espcl=2] \tkzTabInit[lgt=2,espcl=2]
{$ x $/1,$ f(x) $/2}{-1, 2, 3, 5} {$ x $/1,$ f(x) $/2}{-1, 2, 3, 5}
\tkzTabLine{, +, z, +, z, -, d, + , } \tkzTabLine{, +, z, +, z, -, d, + , }
\end{tikzpicture} \end{tikzpicture}
\end{verbatim} \end{verbatim}
\columnbreak \columnbreak
\begin{tikzpicture}[baseline=(a.north)] \begin{tikzpicture}[baseline=(current bounding box.south)]
\tkzTabInit[lgt=2,espcl=2] \tkzTabInit[lgt=2,espcl=2]
{$ x $/1,$ f(x) $/2}{-1, 2, 3, 5} {$ x $/1,$ f(x) $/2}{-1, 2, 3, 5}
\tkzTabLine{, +, z, +, z, -, d, + , } \tkzTabLine{, +, z, +, z, -, d, + , }
@ -240,19 +240,18 @@ Quand on change la valeur de \verb+xstep+, il faut replacer \verb+x+ par \verb+\
\begin{multicols}{2} \begin{multicols}{2}
\begin{verbatim} \begin{verbatim}
\begin{tikzpicture}[baseline=(a.north)] \begin{tikzpicture}[baseline=(current bounding box.south)]
\tkzTabInit[lgt=2,espcl=2] \tkzTabInit[lgt=2,espcl=2]
{$ x $/1, $ f(x) $/2}{-2, 0, 1 } {$ x $/1, $ f(x) $/2}{-2, 0, 1 }
\tkzTabVar{ +/3, -/1, +/5} \tkzTabVar{ +/3, -/1, +/5}
\end{tikzpicture} \end{tikzpicture}
\end{verbatim} \end{verbatim}
\columnbreak \columnbreak
\begin{tikzpicture}[baseline=(a.north)] \begin{tikzpicture}[baseline=(current bounding box.south)]
\tkzTabInit[lgt=2,espcl=2] \tkzTabInit[lgt=2,espcl=2]
{$ x $/1, $ f(x) $/2}{-2, 0, 1 } {$ x $/1, $ f(x) $/2}{-2, 0, 1 }
\tkzTabVar{ +/3, -/1, +/5} \tkzTabVar{ +/3, -/1, +/5}
\end{tikzpicture} \end{tikzpicture}
\end{multicols} \end{multicols}